<span>R= 8.314 J/mol K
T= 273 + 102 = 375K</span><span>
= (3/2) x 8.314 x 375 = 4680 J/mol</span>
Answer:
The Two reasons are :-
1. Combustion efficiency
2. Standardization of test conditions as non-luminous flame.
Explanation:
A luminous flame isn't suitable for heating as it gives out soot (A black powdery or flaky substance consisting largely of amorphous carbon, produced by the incomplete burning of organic matter)
(K+ + MnO4- )+(K+ +Cl- )
This would be a one to one ratio as the charges of each component are equal
c is the answer i odnt know the rest im only a sophmore
