The homogeneous, reversible exothermic, liquid-phase reaction A ↔ R is being carried out in a reactor system consisting of two i
deal CSTRs in series. Both reactors operate at 150°C. The molar flow rate of A entering the first CSTR is 55,000 mol/h, the concentration of A in this stream is 6.5 M, and the concentration of R is zero. The fractional conversion of A in the outlet stream from the second CSTR is 0.75. The reaction is first order in both directions. The rate constant for the forward reaction at 150°C is 1.28 h-1 and the equilibrium constant based on concentration at 150°C is 10.0. If the volume of the second CSTR is 10,000 L, what is the required volume of the first CSTR?
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Answer:
Explanation:
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In this case, since the density is computed by dividing the mass of the substance by its occupied volume (d=m/V), we first need to realize that 0.8206 g/mL is the same to 0.8206 kg/L, which means we first need to compute the volume in L:
Then, solving for the mass in d=m/V, we get m=d*V and therefore the mass of gasoline in that full tank turns out:
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