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Marianna [84]
3 years ago
13

Describe a polyhydroxyl alcohol.

Chemistry
1 answer:
Mademuasel [1]3 years ago
8 0
With a name like poly hydroxyl alcohol, it suggests that the alcohol has more than one alcohol group. Thus any alcohol with more than one hydroxyl is a polyhydroxyl alcohol. An example that pops into mind is ethanediol (CH2OHCH2OH) this has 2 hydroxyl groups and is an alcohol, thus a polyhydroxyl alcohol
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Why is copper a popular mineral? Is it in danger of depletion? Use details to support your answer.
laila [671]

Answer:

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7 0
3 years ago
Be sure to answer all parts. What is the [H3O+] and the pH of a buffer that consists of 0.26 M HNO2 and 0.89 M KNO2? (K, of HNO2
Aleksandr-060686 [28]

Answer : The H_3O^+ ion concentration is, 1.12\times 10^{-3}M and the pH of a buffer is, 2.95

Explanation : Given,

K_a=7.1\times 10^{-4}

Concentration of HNO_2 (weak acid)= 0.26 M

Concentration of KNO_2 (conjugate base or salt)= 0.89 M

First we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (7.1\times 10^{-4})

pK_a=4-\log (7.1)

pK_a=3.15

Now we have to calculate the pH of the solution.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[KNO_2]}{[HNO_2]}

Now put all the given values in this expression, we get:

pH=3.15+\log (\frac{0.89}{0.26})

pH=2.95

The pH of a buffer is, 2.95

Now we have to calculate the H_3O^+ ion concentration.

pH=-\log [H_3O^+]

2.95=-\log [H_3O^+]

[H_3O^+]=1.12\times 10^{-3}M

The H_3O^+ ion concentration is, 1.12\times 10^{-3}M

4 0
3 years ago
What is the temperature when ice Melt
kenny6666 [7]

The temperature when ice melts is 32 degrees Fahrenheit.

6 0
3 years ago
Find the atomicity of water.​
Flauer [41]
One molecule of water contains two atoms of hydrogen and one atom of oxygen, the atomicity of water is three.
4 0
3 years ago
Determine how much energy is needed to change 50 g of liquid water at 100°C to steam.
marin [14]

Answer:

Q=113,000J

Explanation:

Hello there!

In this case, since the vaporization process is carried out in order to turn a liquid into a gas due to the addition of heat, we can use the following heat equation involving the heat of vaporization of water or any other substance:

Q=m*\Delta _{vap}H

Thus, since this heat of vaporization for water is 2259.36 J/g, we plug in this amount to obtain the total energy for this process.

Q=50*2259.36 J/g\\\\Q=113,000J

Which is positive due to the necessity of heat.

Regards!

5 0
3 years ago
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