Question

Acellus

Answer 1

Answer:

161

Step-by-step explanation:

Given:

$a_1=1\\ \\a_n=3a_{n-1}+2$

Find: $a_5$

First, find the second term. Substitute n=2:

$a_2=3a_1+2=3\cdot 1+2=3+2=5$

Now, find the third term, substitute n=3:

$a_3=3a_2+2=3\cdot 5+2=15+2=17$

Find the 4th term, substitute n=4:

$a_4=3a_3+2=3\cdot 17+2=51+2=53$

At last, find the fifth term, substitute n=5:

$a_5=3a_4+2=3\cdot 53+2=159+2=161$