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mash [69]
3 years ago
14

1. Compound A contains 14 g of nitrogen for each 16 g of oxygen. Compound B contains 14 g of nitrogen for each 32 g of oxygen. W

hat is the lowest whole-number mass ratio of nitrogen that combines with a given mass of oxygen
Chemistry
1 answer:
Sever21 [200]3 years ago
4 0

Answer:

The lowest whole number mass ratio of nitrogen that combines with a given mass of oxygen is 1:1

Explanation:

In compound A, we have 14 g of nitrogen combine with  16 g of oxygen

In compound B, we have 14 g of nitrogen combine with  32 g of oxygen

Therefore,  we have

                                                                  A                            B

Ratio of molar masses                               14:16                 14:32

Mass of O that combine with 1 g of N       1.14                   2.29

Dividing by the smallest mass ratio          1                        2

Therefore the lowest whole number mass ratio at which oxygen and nitrogen can combine = 1:1.

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zubka84 [21]

Answer:

The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.

Explanation:

There will be a transfer of thermal energy (heat) from the hot metal plate to the surrounding air. This transfer of energy equates to a transfer of kinetic energy in the molecules. As the plate loses heat, the molecules in the plate will lose kinetic energy and slow down. As the surrounding air gains heat, the molecules will gain kinetic energy and speed up.

8 0
3 years ago
100x100 wsbntxrdfdmxnjhdtnvj
CaHeK987 [17]

Answer:

10000

Explanation:

just add the zeros

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6 0
3 years ago
Read 2 more answers
If the half-life of Carbon-14 is 5700 years, how many years would it take a sample to decay from 1 gram to 31.3 mg
andrew-mc [135]

Answer:

28500 years

Explanation:

Applying,

A = A'(2^{x/y})............... Equation 1

Where A = Original mass of Carbon-14, A' = Final mass of carbon-14 after decaying, x = total time, y = half-life.

From the question,

Given: A = 1 g, A' = 31.3 mg = 0.0313 g, y = 5700 years.

Substitute these values into equation 1

1 = 0.0313(2^{x/5700})

2^{x/5700} = 1/0.0313

2^{x/5700}  = 31.95

2^{x/5700} ≈ 32

2^{x/5700} ≈ 2⁵

Equating the base and solve for x

x/5700 ≈ 5

x ≈ 5×5700

x ≈ 28500 years

3 0
3 years ago
142Pm &gt; 142 Nd +<br> what is the answer to this equation
erastova [34]

Explanation:

nnbbnmkmknn bnnnbbtbbbbn' nn' t

4 0
3 years ago
When a aqueous solution of a certain acid is prepared, the acid is dissociated. Calculate the acid dissociation constant of the
stepan [7]
<h2>K_a = \dfrac{[H^{+}] [A^{-}]}{[HA]}</h2>

Explanation:

  • When an aqueous solution of a certain acid is prepared it is dissociated is as follows-

        {\displaystyle {\ce {HA  ⇄  {H^+}+{A^{-}}}  }}

Here HA is a protonic acid such as acetic acid, CH_3COOH

  • The double arrow signifies that it is an equilibrium process, which means the dissociation and recombination of the acid occur simultaneously.
  • The acid dissociation constant can be given by -

        K_a = \dfrac{[H^{+}] [A^{-}]}{[HA]}

  • The reaction is can also be represented by Bronsted and lowry -

         \\{\displaystyle {\ce {{HA}+ H_2O} ⇄  [H_3O^+] [A^-]

  • Then the dissociation constant will be

        K_a = \dfrac{[H_3O^{+}] [A^{-}]}{[HA]}

Here, K_a is the dissociation constant of an acid.

6 0
4 years ago
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