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mash [69]
3 years ago
14

1. Compound A contains 14 g of nitrogen for each 16 g of oxygen. Compound B contains 14 g of nitrogen for each 32 g of oxygen. W

hat is the lowest whole-number mass ratio of nitrogen that combines with a given mass of oxygen
Chemistry
1 answer:
Sever21 [200]3 years ago
4 0

Answer:

The lowest whole number mass ratio of nitrogen that combines with a given mass of oxygen is 1:1

Explanation:

In compound A, we have 14 g of nitrogen combine with  16 g of oxygen

In compound B, we have 14 g of nitrogen combine with  32 g of oxygen

Therefore,  we have

                                                                  A                            B

Ratio of molar masses                               14:16                 14:32

Mass of O that combine with 1 g of N       1.14                   2.29

Dividing by the smallest mass ratio          1                        2

Therefore the lowest whole number mass ratio at which oxygen and nitrogen can combine = 1:1.

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love history [14]

Answer:

m=1.325gNa_2CO_3

Explanation:

Hello,

In this case, by considering the given seminormal solution, we infer it is a 0.5-N solution which means that we can obtain the equivalent grams as shown below for the 55 cc (0.055 L) volume:

eq-g=0.5eq-g/L*0.050L=0.025eq-g

Next, since sodium carbonate has two sodium ions with a +1 oxidation state each, we can obtain the moles:

mol=0.025eq-gNa_2CO_3*\frac{1molNa_2CO_3}{2eq-gNa_2CO_3}\\ \\mol=0.0125molNa_2CO_3

Finally, the mass is computed by using its molar mass (106 g/mol)

m=0.0125molNa_2CO_3*\frac{106gNa_2CO_3}{1molNa_2CO_3} \\\\m=1.325gNa_2CO_3

Regards.

7 0
3 years ago
what is the change in the velocity of the biker below as he travels from point b to point c ? ..... What is his acceleration fro
Furkat [3]

The change in the velocity = 4 m/s

Acceleration = 4 m/s²

<h3>Further explanation</h3>

Given

vo = initial velocity = 4 m/s

vf = final velocity = 8 m/s

t = 1 s

Required

The change in the velocity

Acceleration

Solution

the change in velocity =

\tt vf-vo=8-4=4~m/s

Acceleration = ratio of a change in velocity and the time

\tt a=\dfrac{\Delta v}{t}= \dfrac{vf-vo}{t}

Input the value :

\tt a=\dfrac{4~m/s}{1~s}=4~m/s^2

7 0
2 years ago
Some animals only have ___ cell.
DaniilM [7]
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3 0
3 years ago
Nitrogen dioxide is produced by combustion in an automobile engine. For the following reaction, 0.377 moles of nitrogen monoxide
Contact [7]

Answer:

The amount of NO₂ that can be produced 8.533 g

Explanation:

       According to question

                                2 NO(g) + O₂(g) → 2 NO₂(g)

Given

Moles of nitrogen monoxide = 0.377

Moles of oxygen = 0.278

'For NO'=\frac{Mole}{Stoichiometry}=\frac{0.377}{2} =0.1855\\'For O_{2} '=\frac{0.278}{1}= 0.278\\

Since 'NO' is the limiting reagent according to this ratio.

According to equation

         2 moles NO reacts to form 2 moles NO₂

So,  0.1855 moles NO give  = 0.1855 moles of NO₂

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            Mass of 0.1855 moles = 46 x 0.1855 = 8.533 g

5 0
3 years ago
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