Answer: ok that was i am doing
Explanation: like help them
Answer:
See explanation
Explanation:
The nucleophile here is CH3OH. We know that CH3OH is a good nucleophile that promotes SN2 reanction. However, (R)-6-bromo-2,6-dimethylnonane is a tertiary alkyl halide so the reaction proceeds by SN1 mechanism. This means that a racemic mixture is obtained at the end of the reaction because the attack occurs at the stereogenic carbon atom (6R) hence the product is optically inactive.
On the other hand, when (5R)-2-bromo-2,5-dimethylnonane is reacted with CH3OH, an optically active product is obtained because; though a tertiary alkyl halide and reaction occurs by SN1 mechanism, the attack does not occur at the stereogenic carbon atom (5R). Therefore, an optically active product is obtained in this case.
Oil, petroleum
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Answer:
Precipitates are in option a and b
Explanation:
These are the chemical reactions:
a. Pb²⁺ + CO₃⁻² → PbCO₃ ↓
b. Pb²⁺ + 2I⁻ → PbI₂ ↓
c. Fe³⁺ + 3Cl⁻ → FeCl₃
d. Cu²⁺ + SO₄⁻² → CuSO₄
e. Al³⁺ + 3Cl⁻ → AlCl₃
Iodides, chlorides and bromides are soluble except the ones with Ag, Pb and Hg
All the carbonates are insolubles except the alkali carbonates.
All the sulfates are solubles except the one that are formed with Group II (Ba, Ca and Mg)
