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Elden [556K]
3 years ago
10

An ionic bond would form between which pairs of elements? atomic number 4 and atomic number 18 atomic number 7 and atomic number

8 atomic number 3 and atomic number 4 atomic number 8 and atomic number 12
Chemistry
1 answer:
weeeeeb [17]3 years ago
4 0

Answer:

atomic number 8 and atomic number 12

Explanation:

atomic number 8 and atomic number 12 , element with the atomic number 8 is oxygen, and the element with atomic number 12 is Magnesium

Magnesium has low ionization energy, hence higher tendency to loose its two outermost electrons to form positive ion.

Oxygen has high electron affinity, hence higher tendency to accept or gain electrons to form negative ion.

The electronegativity difference between the element with atomic number 8 and element with atomic number 12 is greater for the formation of ionic bond

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Answer:

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Explanation:

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3 years ago
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Use the information provided to determine ΔH°rxn for the following reaction: ΔH°f (kJ/mol) 3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2
zepelin [54]

Answer:

ΔH°rxn = -47 kJ

Explanation:

Using Hess´s law for the reaction:

3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(g) ,

the ΔH°rxn will be given by the expression:

ΔH°rxn kJ  =   2ΔHºf(Fe3O4)  + ΔHºf(CO2)   - ( 3ΔHºf(Fe2O3) + ΔHºf(CO) )

=  2(-1118) + (-394) - ( 3( -824 ) + ( -111 ) )

= - 47 kJ

3 0
3 years ago
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When dipentyl ether is treated with HI, what type of reaction occurs? both SN1 and SN2 SN2 E1 SN1 E2
masha68 [24]

Answer:

SN2

Explanation:

The first step of ether cleavage is the protonation of the ether since ROH is a better leaving group than RO-.

The second step of the reaction may proceed by either SN1 or SN2 mechanism depending on the structure of the ether. Methyl and primary ethers react with HI by SN2 mechanism while tertiary ethers react with HI by SN1 mechanism. Secondary ethers react with HI by a mixture of both mechanisms.

Dipentyl ether is a primary ether hence when treated with HI, the reaction with HI proceeds by SN2 mechanism as explained above.

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A 1.0 g sample of hydrogen reacts completely with 19.0 g of fluorine to form a compound of hydrogen and fluorine. a. What is the
Rashid [163]

Explanation:tr

a) Molar mass of HF = 20 g/mol

Atomic mass of hydrogen = 1 g/mol

Atomic mass of fluorine = 19 g/mol

Percentage of an element in a compound:

\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{Molar mass of compound }}\times 100

Percentage of fluorine:

\frac{1\times 19 g/mol}{20g/mol}\times 100=95\%

Percentage of hydrogen:

\frac{1\times 1g/mol}{20 g/mol}\times 100=5\%

b) Mass of hydrogen in 50 grams of HF sample.

Moles of HF = \frac{50 g}{20 g/mol}=2.5 mol

1 mole of HF has 1 mole of hydrogen atom.

Then 2.5 moles of HF will have:

1\times 2.5 mol=2.5 mol of hydrogen atom.

Mass of 2.5 moles of hydrogen atom:

1 g/mol × 2.5 mol = 2.5 g

2.5 grams of hydrogen would be present in a 50 g sample of this compound.

c) As we solved in part (a) that HF molecules has 5% of hydrogen by mass.

Then mass of hydrogen in 50 grams of HF compound we will have :

5% of 50 grams of HF = \frac{5}{100}\times 50 g=2.5 g

8 0
3 years ago
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