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Cloud [144]
3 years ago
8

What would be your best course of action if exposed to this hazard?

Chemistry
1 answer:
Olenka [21]3 years ago
6 0

Answer: Option C) Rinse the affected area with cool water for 10-15 minutes.

Explanation:

Once exposed to burns, whether chemical or heat, rinse the affected area of the body with cool water, as water is known to dissolve all burning particles attached to the skin, and cool off the blood vessels lying beneath the burned surface.

Unlike other options provided, rinsing affected area with cool water is the best first aid for skin burns

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How many grams of fluorine are needed to generate 7.65 moles Carbon Tetrafluoride
Delicious77 [7]

Answer:

36.3375 g

Explanation:

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2 years ago
How to tell which element is oxidized in a reaction?
adoni [48]
If in a redox reaction oxidation state of elements decreases or looses electron(s), the element is said to be oxidized. Hope this helps you!
4 0
3 years ago
 Consider a bathtub filled with water, with a plug in the drain. How long would this be considered a closed system?
Monica [59]
For a closed system, you need two things:
1) a conservation of mass within the boundaries of the system
2) the ability to freely exchange energy to & from the "closed" system with a surrounding external system


So, the answer is <u><em>never</em></u>, since your defining the "system" as the water within the bathtub, and an open bathtub is exposed to evaporation, which is not conserving mass within the defined "system".
8 0
3 years ago
Read 2 more answers
The decomposition of mercury (ii) oxide at high temperature, is it an endothermic or exothermic process? Write a chemical reacti
gulaghasi [49]

Answer:

that will be endothermic reaction...... as oxides of mercury decomposes and break s into simpler elements by absorbing energy

Explanation:

hope it helped u buddy

6 0
2 years ago
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A 0.24g sample of compound of oxygen and boron was found by analysis to contain 0.144g of Oxygen.calculate the percentage compos
oksano4ka [1.4K]

Answer:

Mass of compound = 0.24 g and, mass of boron = 0.096 g percentage of boron in the compound = mass of boron / mass of compound * 100 = 0.096/0.24 * 100 = 40% mass of oxygen = 0.144 g again, mass of compound = 0.24 g percentage of oxygen in compound = mass of oxygen/mass of of compound * 100 = 0.144/0.24 * 100 = 60%

<h2>Hope it's Helpful!!✌️</h2>
5 0
2 years ago
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