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solmaris [256]
3 years ago
10

What is 13.89 rounded to the nearest thousandth?

Mathematics
1 answer:
Musya8 [376]3 years ago
7 0
13.8900 this is the answer. it is like this because thousandth is.0000. it Cant be 13.0089 because you would change the number.
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Ksivusya [100]

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Step-by-step explanation:

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3 years ago
The solution to the system is (6,2) Select all the equations that could be the other equation in the system. PLZ HELPPPPPP there
Dovator [93]

9514 1404 393

Answer:

  A, C

Step-by-step explanation:

The attached graph shows which lines go through the given point. They are ...

  y = 1/2x -1 . . . . 1st selection

  y = -1/6x +3 . . . 3rd selection

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The equations can be found algebraically by substituting the given point in the equation and seeing if the result is a true statement.

  a) 2 = (1/2)(6) -1 = 3 -1 . . . true

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  c) 2 = -1/6(6) +3 = -1 +3 . . . true

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6 0
3 years ago
Given a soda can with a volume of 15 and a diameter of 2, what is the volume of a cone that fits perfectly inside the soda can?
Naddika [18.5K]
Check the picture below.

so, a cone, that fits inside the cylinder, will have the same height "h" and radius "r".  Thus


\bf \textit{volume of a cylinder}\\\\
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\\\\\\
\textit{volume of a cone}\\\\
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8 0
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6 0
3 years ago
Read 2 more answers
Which of these relations on {0, 1, 2, 3} are equivalence relations? Determine the properties of an equivalence re- lation that t
slava [35]

Answer:

The relations that are equivalence relations are a) and c)

Step-by-step explanation:

A relation on a set A is called an equivalence relation if it is reflexive, symmetric, and transitive

We are going to analyze each one.

a){ (0,0), (1,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

b){ (0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3) }

Is not an equivalence relation. Not reflexive: (1,1) is missing, not transitive: (0,2) and (2,3) are in the relation, but not (0,3)

c){ (0,0), (1,1), (1,2), (2,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

d){ (0,0), (1,1), (1,3), (2,2), (2,3), (3,1), (3,2) (3,3) }

Is not an equivalence relation. Not transitive: (1,3) and (3,2) are in the relation, but not (1,2)

e){ (0,0), (0,1) (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3) }

Is not an equivalence relation. Not symmetric: (1,2) is present, but not (2,1)Not transitive: (2,0) and (0,1) are in the relation, but not (2,1)

5 0
3 years ago
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