2/16
BC there are 2 red marbles out of 16 marbles in total
Answer:
<u>Problem 4:</u> Option C, 32
<u>Problem 5:</u> You need to have the 2 and the x combine. Make the table 2x than 16.
<u>Problem 6:</u> x = 17
<u>Problem 7:</u> She drew a 2, x and an 16. Instead you must have 2x and 16. 2x + 16 = 50
Step-by-step explanation:
<u>Problem 4</u>
2 + x + 16 = 50
x + 18 - 18 = 50 - 18
x = 32
Answer: Option C, 32
<u>Problem 5</u>
You need to have the 2 and the x combine. Make the table 2x than 16.
Answer: You need to have the 2 and the x combine. Make the table 2x than 16.
<u>Problem 6</u>
2x + 16 - 16 = 50 - 16
2x / 2 = 34 / 2
x = 17
Answer: x = 17
<u>Problem 7</u>
She drew a 2, x and an 16. Instead you must have 2x and 16. 2x + 16 = 50
Answer: She drew a 2, x and an 16. Instead you must have 2x and 16. 2x + 16 = 50
The quadrant that the graph will not go through is the second quadrant.
The reason is that the slope is positive and there was a translation 6 units down
<h3>How to know the quadrant the graph will not pass</h3>
The quadrants are named in anticlockwise direction starting from the first which has x - positive and y - positive
The graph of y = 2x/3 is a graph with positive slope, moving through the third and first quadrant.
y = 2x/3 - 6 means a translation 6 units down and this pushed the line to get to the fourth quadrant
Hence the remaining quadrant that is untouched is the second quadrant
The graph is attached
learn more about graphs here:
brainly.com/question/25184007
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Answer:
C
Step-by-step explanation:
The formula for finding the distance between 2 points (x1, y1) and (x2, y2) is
d = √[(x2 - x1)² + (y2 - y1)²]
Here (x2, y2) = (2, 3) and (x1, y1) = (4, -3)
Plugging them gives us
d = √[(2 - 4)² + (3 - (-3))²]
d = √[(2 - 4)² + (3 + 3)²]