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IgorC [24]
3 years ago
5

Find the solution for m such that:

%7D%20%20%7D%20%20%3D%20%20x%5E%7Bm%7D%3Cbr%3E%3Cbr%3E%0A%20%20" id="TexFormula1" title=" \frac{1}{ \sqrt[3]{ x^{2} } } = x^{m}
 " alt=" \frac{1}{ \sqrt[3]{ x^{2} } } = x^{m}
 " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Leviafan [203]3 years ago
5 0
Let's raise the exponent three on both sides of the equation.

1/x^2 = (x^m)^3

1/x^2 = x^(3m)

1 = x^2.x^(3m)

1 = x^(2+3m)

X^(2+3m) = 1

For this to be true:

2+3m = 0

3m = -2

m = -2/3
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Rate of commission
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3 years ago
What is the measure of angle A in the triangle?<br><br> ​ m∠A = ___°
Firdavs [7]
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180° - 70° = (2x-10°) + (x+30°)
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8 0
3 years ago
Read 2 more answers
Easy math, need the explanation &amp; the answer. pls n thx
Karo-lina-s [1.5K]
D is the awnser for this one
8 0
3 years ago
Find the total number of diagonals in a regular nonagon.
anastassius [24]

Answer:

7

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3 0
3 years ago
Is the HCF of a^3-8, a^4+16 and a^3+2a^2+4a just 1?<br> Please answer........
Flauer [41]
First we find the factors
a^3-8 is the differnce between 2 perfect cubes and is factored out to
(a-2)(a^2+2a+4)
the factors are (a-2) and (a^2+2a+4)

a^4+16
this is not factorable, unless you mistiped it and it was really a^4-16
the factor is 1


a^3+2a^2+4a
factor out the a
a(a^2+2a+4)
this is the most factored out form
the factors are (a) and (a^2+2a+4)


there are no common factors except 1 so 1 is the answer
3 0
3 years ago
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