<span>draw the figure first (label everything you know).
add two altitudes, from the endpoints of the top base
you know that the bottom base is now divided 5-6-5
using that and the diagonal, pythagorean theorm can be used to find the altitude:
(c^2)-(a^2)=(b^2)
(12^2)-(11^2)=b^2
b^2=23
altitude is about 4.8</span>
Answer:
h(2) = 0
Step-by-step explanation:
To evaluate h(2) , substitute x = 2 into h(x), that is
h(2) = - 2 + 2 = 0
Note that c is the hypotenuse of the blue triangle, and that the Pyth. Thm. states that (length of one leg)^2 + (length of the other leg)^2 = (hyp)^2.
Therefore, (hyp)^2 = c^2 = [2sqrt(x^2+3x)]^2 + 3^2, or
= 4(x^2+3x) + 9, or
= 4x^2 + 12x + 9 = (2x+3)^2
Taking the sqrt of both sides, c = plus or minus (2x+3). Eliminate -(2x+3) because the middle term of the square of this would be negative, in conflict with the given +12x.
c=2x+3 is the correct answer.
Answer:
-4r
Step-by-step explanation:
r + (-5r)
1r + (-5r)
Factor out an r
r( 1 -5)
One minus 5 is negative 4. If you have one dollar and you borrow five dollars, how much did you borrow? 4 but that 4 is borrowed so it is negative
r (-4)
-4r
