Answer: The answer is A, A new element or different atom formed from the original two.
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-<em>TanqR</em>
Answer:
The empirical formula is PCl3
Explanation:
Mass of P is 30.97 g, thus 1.523 g of P equivalent to 0.05 moles of P
Mass of Cl is 35.45 g, thus 5.228 g of Cl equivalent to 0.15 moles of Cl
Therefore moles of P : moles of Cl = 0.05:0.15 = 1:3
Therefore the empirical formula, PCl3
Answer:
0.7 moles of Ca(OH)₂ are produced.
Mass of hydrogen gas = 1.4 g
Explanation:
Given data:
Mass of water = 25.0 g
Mass of hydrogen gas produced = ?
Number of moles of Ca(OH)₂ formed = ?
Solution:
Chemical equation:
Ca + 2H₂O → Ca(OH)₂ + H₂
Number of moles of water:
Number of moles = mass/molar mass
Number of moles = 25.0 g/ 18 g/mol
Number of moles = 1.4 mol
Now we will compare the moles of water with hydrogen:
H₂O : H₂
2 : 1
1.4 : 1/2×1.4 = 0.7 mol
Mass of hydrogen gas produced:
Mass = number of moles × molar mass
Mass = 0.7 mol × 2 g/mol
Mass = 1.4 g
Now we will compare the moles of water and Ca(OH)₂
H₂O : Ca(OH)₂
2 : 1
1.4 : 1/2×1.4 = 0.7 mol
Thus, 0.7 moles of Ca(OH)₂ are produced.
Answer:
M=0.02
Explanation:
85 g NaNO3 -> 1 mol NaNO3
0.45 g NaNO3 ->x
x=(0.45 g NaNO3 * 1 mol NaNO3)/85 g NaNO3 x= 5.3 x 10^-3 mol
265 mL= 0.265 L
M= mol solute/ L solution
M= 5.3 x 10^-3 mol NaNO3/0.265 L M=0.02
