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Vsevolod [243]
3 years ago
11

A sample of hydrogen gas has a volume of 10.0 liters at 95.0 kPa and 298 K. If temperature remains constant, what is the volume

of the sample at 101.3kPa
Chemistry
1 answer:
pogonyaev3 years ago
3 0

Answer: 9.38L

Explanation: V1 = 10L

P1 = 95.0 kPa

V2 =?

P2= 101.3kPa

P1V1 = P2V2

10 x 95 = 101.3 x V2

V2 = 950/101.3

V2 = 9.38L

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What descriptive term is applied to the type of diene represented by 1,5-octadiene?
Mrac [35]

The descriptive term that is applied to the type of diene represented by 1,5-octadiene is isolated diene. The correct option is C.

<h3>What is diene?</h3>

Diene is a compound that contains two or more double bonds, usually  carbon bonds, which are separated by a single bond. They are covalent compounds. Alkene units are surely present in these compounds, whose quantity is two.

1,5-octadiene is a polymer of diene, which are generally elastomers, and they made of vulcanized rubber. They are isolated diene.

Thus, the correct option is C) Isolated diene.

To learn more about diene, refer to the below link:

brainly.com/question/17425564

#SPJ4

The question is incomplete. The complete question is given below:

A) Conjugated diene.

B) Cumulated diene.

C) Isolated diene.

D) Alkynyl diene.

E) None of the above.

3 0
9 months ago
A chemist prepares a sample of helium gas at a certain pressure, temperature and volume and then removes all but a fourth of the
cupoosta [38]

Answer:

The temperature must be changed to 4 times of the initial temperature so as to keep the pressure and the volume the same.

Explanation:

Pressure in the container is P and volume is V.

Temperature of the helium gas molecules =T_1

Molecules helium gas = x

Moles of helium has = n_1= \frac{x}{N_A}

PV = nRT (Ideal gas equation)

PV=n_1RT_1...[1]  

After removal of helium gas only a fourth of the gas molecules remains and pressure in the container and volume should remain same.

Molecules of helium left after removal = \frac{x}{4}

Moles of helium has left after removal = n_2= \frac{x}{4\times N_A}

PV=n_2RT_2...[2]

n_1RT_1=n_2RT_2

\frac{x}{N_A}\times T_1=\frac{x}{4\times N_A}\times T_2

T_1=\frac{T_2}{4}

T_2=4T_1

The temperature must be changed to 4 times of the initial temperature so as to keep the pressure and the volume the same.

6 0
3 years ago
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Cerrena [4.2K]

Answer:

  • Sodium Bicarbonate (β-3) + Vinegar
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Explanation:

Baking Soda and vinegar cause an explosion, in which the bicarbonate and vinegar are replaced by nitrate (∨) and oxide (Ф.) When you combine lead nitrate (Δω) with potassium iron, you also see the ingredients you combined disappear, which shall cause a replace reaction

6 0
2 years ago
Your sick puppy is diagnosed with roundworms. They grow inside of the puppy. What type of symbiotic relationship do the puppy an
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D. Parasitism , the roundworm benefits from the relationship, but the puppy is harmed
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3 subatomic particles in the nucleus
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