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musickatia [10]
3 years ago
15

13. "The business of America is business.” — President Calvin Coolidge.

Chemistry
1 answer:
LenKa [72]3 years ago
4 0

Answer:

<h3>Answer is </h3>

A higher taxes on corporations

<h2 /><h2 /><h2>I hope you like it </h2>

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The greater the mass of an object
andreyandreev [35.5K]
The greater the mass of an object, the greater<span> its gravitational force.
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6 0
3 years ago
write the balanced molecular chemical equation for the reaction in aqueous solution for sodium hydroxide and tin(iv) acetate. if
dimaraw [331]

The reaction of Sodium hydroxide and Tin(iv) acetate is as follows:

Sodium Hydroxide + Tin(IV) Acetate = Sodium Acetate + Tin(IV) Hydroxide

NaOH + Sn(C2H3O2)4 = C2H3NaO2 + Sn(OH)4

<u>Balanced Chemical Equation</u>:

4NaOH + Sn(C2H3O2)4 → 4C2H3NaO2 + Sn(OH)4

What is an Aqueous solution?

An aqueous solution is one in which water serves as the solvent. It is also known as a water-based solution. Many common chemical substances are dissolved in water, and these are called aqueous solutions. Examples of aqueous solutions include saltwater, vinegar, and sugar water.

What is Sodium hydroxide?

Sodium hydroxide, also known as lye or caustic soda, is a white, solid crystalline substance used in a number of industrial and household applications. It is a strong base that is highly soluble in water and can be used to adjust the pH of a solution. It is also used in the manufacture of soaps, detergents, and cleaning products.

What is Tin(IV)?

Tin(IV) is the chemical name for tin, which is a chemical element with the atomic number of 50. It is a silvery-white, malleable metal that is used in a variety of applications, including alloys, solders, and some electronics.

To know more about Sodium hydroxide,

LINK- brainly.com/question/29509565

CODE- #SPJ4

5 0
1 year ago
How many moles of oxygen are needed to react with 87 grams of aluminum
labwork [276]

Answer:

2.4 moles of oxygen are needed to react with 87 g of aluminium.

Explanation:

Chemical equation:

4Al(s)  + 3O₂(l)   → 2AlO₃(s)

Given data:

Mass of aluminium = 87 g

Moles of oxygen needed = ?

Solution:

Moles of aluminium:

Number of moles of aluminium= Mass/ molar mass

Number of moles of aluminium= 87 g/ 27 g/mol

Number of moles of aluminium= 3.2 mol

Now we will compare the moles of aluminium with oxygen.

                              Al         :         O₂

                               4          :         3

                               3.2       :         3/4×3.2 = 2.4 mol

2.4 moles of oxygen are needed to react with 87 g of aluminium.

5 0
3 years ago
Need help with these two pls!!
denis23 [38]

what is a fire piston?

*a tool for starting a fire, likely invented in Ancient Southeast Asia.*

dont know the second one lol.

8 0
3 years ago
How many “dots” would be around the central atom in the Lewis structure of S?
agasfer [191]
B) 6
one above one below and 2 on the left and right sides
6 0
3 years ago
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