Hello There!
Let's first talk about <em>"What Is Friction"</em>
<u>Friction is a force that pulls when two object touch each-other. Friction happens because the molecules on one surface interlock with the molecules on another surface.</u>
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Now, let's get back to our original question "What Effect Does Friction Have On A Roller Coaster"
On a roller coaster, friction is a force that opposes motion and significantly slows the cars as they move on the track.
General formula for emf is : emf = vBL (sin 0)...(1)
As the angle here is 90º and sin90º =1.
So, equation (1) becomes : emf = vBL Putting values :
emf = (6.2)(1.5)(3.96 * 10<span>^-3) = 0.0369 volts
</span>Hope this helps:)
The velocity of the combined mass after the collision is 0.84 ms-1.
<u>Explanation:</u>
According to law of conservation of momentum, the change in momentum before collision will be equal to the change in momentum of the objects after collision in isolated system.
But as it is perfectly inelastic collision in the present case, the final momentum will be based on the product of total mass of both the object with the velocity with which the collision occurred. This form is attained from the law of conservation of momentum as shown below:
So as law of conservation of momentum,
Here 
= 3 kg and 
= 2 kg are the masses of objects 1 and 2, 
= 1.4 m/s and 
= 0 are the initial velocities of object 1 and object 2, 
and 
are the final velocities of the objects.
So after collision, object 1 get sticked to object 2 and move together with equal velocity = = 
. Thus the above equation will become,
So the final velocity is
Thus,
= 0.84 ms-1.
We use the kinematics equation:
Vf = Vi + a*t
8 = 0 + 3.6 * t
t=2.222s to reach 8.0 m/s
At that time the train has moved
4.5 m/s * 2.222s = 9.999 m
He travelled (another kinematics equation)
Vf^2 = Vi^2 + (2*a*d)
(8.0)^2 = (0)^2 + (2 * 3.6 * d)
d=8.888 m
The train is 9.999m, the fugitive is 8.888m,
He still needs to travel
9.999-8.888= 1.111m
He needs to cover the rest of the distance in a smaller amount of time, however hes at his maximum velocity, so...
8m/s(man) - 4.5m/s(train) = 3.5 m/s more
(1.111m) / (3.5m/s) = .317seconds more to reach the train
So if it takes 2.222 seconds to approach the train at 8.888m, it should take
2.222 + .317 =2.529 seconds to reach the train completely
Last but not least is to figure out the total distance traveled in that time frame:
(Trains velocity) * (total time)
(4.5m/s)*(2.529s)=11.3805m
The answer is calcium. I just did it and it was correct
