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konstantin123 [22]
3 years ago
9

A swimmer swims a half lap, moving from the left end to the right end of a pool that is 50 meters long. What is the Distance and

Displacement?
Physics
1 answer:
lina2011 [118]3 years ago
6 0
<h2><u>Answer</u>:</h2>

Distance = 50m

Displacement = 50m to the right

<h2><u>Explanation</u>:</h2>

<em>Distance</em> is the total length of a given path. It is a scalar quantity and thus takes no consideration on the direction of the path.

<em>Displacement</em> on the other hand is the change in position of an object. It is a vector quantity and takes consideration on the direction of the object.

From the question:

<em>The swimmer swims half lap by moving from the left end to the right end of a pool that is 50m long.</em>

Distance = total length of the given path = 50m

Displacement = change in position of the swimmer from the left end (0m) to the right end (50m) = 50 - 0 = 50m

Since direction is important in displacement, the complete details of the displacement should be 50m to the right

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A woman in a sprint race accelerates from rest to 8.7 m/s in 2.7 s. What is her displacement?​
Trava [24]

Answer:

23.49m

Explanation:

Distance =  velocity x time

8.7 x 2.7 = 23.49m

8 0
3 years ago
The time taken for an object to fall from a height of h m from the earth'fs surface is t s.
telo118 [61]

Answer:

B. Longer than t s,

Explanation:

Gravitational accln on earth is 9.8 m/s^2,

and one you provided as on moon is 1.6 m/s^2

that mean on moon gr. accl. is lesser!

now the time taken on earth will be lesser cuz from the same height if you drop the object from rest!

since accln on earth is higher,the object will attain higher velocity as compare to that of on moon!

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6 0
3 years ago
A roller coaster car rapidly picks up speed as it rolls down a slope. As it starts down the slope, its speed is 4m/s. But 3 seco
slamgirl [31]

Answer:

6 m/s^2

Explanation:

The average acceleration of the car is given by:

a=\frac{v-u}{t}

where

v is the final speed

u is the initial speed

t is the time elapsed

For the car in this problem,

v = 22 m/s

u = 4 m/s

t = 3 s

Therefore, the acceleration of the car is

a=\frac{22 m/s-4 m/s}{3 s}=6 m/s^2

7 0
3 years ago
A gas takes up a volume of 17.0 L, has a pressure of 2.30 atm, and a temperature of 299 K. If the temperature is raised to 350.0
Maurinko [17]

Answer:

new volume = 30.513L

Explanation:

V1 =17L , P1= 2.3atm ,  T1=299K ,  T2=350K , P2 =1.5atm,   V2=?

To find the new volume of the gas we will use the combined gas law.

The combined gas law combines Boyle's law, Charles law and Gay-Lussac's law. Its states that the ratio of the product of pressure and volume to temperature is equal to a constant. its expressed mathematically below.

\frac{V1P1}{T1} = \frac{V2P2}{T2}

V2 =\frac{V1P1T2}{P2T1}

V2 =\frac{17*2.3*350}{1.5*299}

v2 = \frac{13685}{448.5}

V2 =30.513L

4 0
3 years ago
Read 2 more answers
Estimate the kinetic energy (in GJ) of a 98,000 metric ton aircraft carrier moving at a speed of at 32 knots. You will need to l
kiruha [24]

Answer:

K = 13.276 GJ

Explanation:

Given:

Mass of the aircraft (m) = 98,000 metric ton

Speed of the aircraft (v) = 32 knots

Kinetic energy of the aircraft (K) = ?

We know that,

1 metric ton = 1000 kg

∴ 98,000 metric ton = 98,000 × 1000 = 9.8 × 10⁷ kg

Also, 1 knot = 1 nautical mile per hour

So, 32 knots = 32 nautical miles per hour

Converting nautical miles per hour to meter per second using the following conversions, we get:

1 nautical mile = 1852 m

1 hour = 3600 s

Therefore, 1 nautical mile per hour = \frac{1852}{3600}\ m/s

So, 32 nautical miles per hour = 32\times \frac{1852}{3600}=16.46\ m/s

Therefore, the mass and speed of the aircraft are:

m=9.8\times 10^{7}\ kg\\v=16.46\ m/s

Now, kinetic energy is given as:

K=\frac{1}{2}mv^2

Plug in the above values and solve for 'K'. This gives,

K=\frac{1}{2}\times 9.8\times 10^7\times (16.46)^2\\\\K=4.9\times 270.9316\times 10^7\ J\\\\K=13.276\times 10^2\times 10^7\ J\\\\K=13.276\times 10^9\ J

Now, we know that, 1 GJ = 10⁹ J

Therefore, the value of 'K' in terms of GJ is given as:

K = 13.276 GJ

8 0
3 years ago
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