The answer is D.

Velocity is the speed in a particular direction.

Saying that you are going from Los Angeles to Catalina Island is not a particular direction, it is an end destination.

3 0

3 years ago

A 591 μF capacitor is discharged through a resistor, whereby its potential difference decreases from its initial value of 88.5 V

Stels [109]

Answer:

2.6 kilo Ohm

Explanation:

Capacitance, C = 591 μF = 591 x 10^-6 F

Vo = 88.5 V

V = 11.9 V

t = 3.09 s

Let the resistance is R.

$V = V_{0}e^{\frac{-t}{RC}}$

$\frac{11.9}{88.5} = e^{\frac{-t}{RC}}$

$0.135 = e^{\frac{-t}{RC}}$

Take natural log on oth the sides

ln 0.135 = - 3.09 / RC

RC = 1.545

R = 1.545 / ( 591 x 10^-6)

R = 2614.2 ohm

R = 2.6 kilo Ohm

Thus the resistance is 2.6 kilo Ohm.

8 0

3 years ago

A 25.0 kg block is initially at rest on a horizontal surface. A horizontal force of 75.0 N is required to set the block in motio

QveST [7]

Answer:

(a) 0.31

(b) 0.245

Explanation:

(a)

F' = μ'mg.................... Equation 1

Where F' = Horizontal Force required to set the block in motion, μ' = coefficient of static friction, m = mass of the block, g = acceleration due to gravity.

make μ' the subject of the equation above

μ' = F'/mg............. Equation 2

Given: F' = 75 N, m = 25 kg

constant: g = 9.8 m/s²

Substitute these values into equation 2

μ' = 75/(25×9.8)

μ' = 75/245

μ' = 0.31.

(b) Similarly,

F = μmg.................. Equation 3

Where F = Horizontal force that is required to keep the block moving with constant speed, μ = coefficient of kinetic friction.

make μ the subject of the equation

μ = F/mg.............. Equation 4

Given: F = 60 N, m = 25 kg, g = 9.8 m/s²

Substitute these values into equation 4

μ = 60/(25×9.8)

μ = 60/245

μ = 0.245

3 0

3 years ago

Beat frequency problem. Your ear simultaneously hears waves from different sources, so it can hear beats from the two speakers.

podryga [215]

Completed question:Suppose one speaker is driven at 570 Hz and the other at 554 Hz. What is the beat frequency in Hz? The average frequency in Hz?

Answer:

Beat frequency= 16Hz

Average frequency = 562Hz

Explanation:

Beat frequency f = f2-f1

Where f2 is frequency of source with higher frequency

f1 is frequency of source with lower frequency

f1= 554Hz, f2= 570Hz

beat frequency (f) = 570 -554

= 16Hz

Average frequency = $\frac{554+570}{2}$

= $\frac{1124}{2}\\ =562Hz$

5 0

3 years ago