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emmainna [20.7K]
3 years ago
11

A golf ball is dropped from rest from a height of 8.40 m. It hits the pavement, then bounces back up, rising just 5.60 m before

falling back down again. A boy then catches the ball when it is 1.40 m above the pavement. Ignoring air resistance, calculate the total amount of time that the ball is in the air, from drop to catch.

Physics
1 answer:
allochka39001 [22]3 years ago
5 0

Answer:

t1= 8.40/10 =.84 s

t2 = 5.60/10 = .56s

t3= 1.4/10 = .14s

total time = 1.54 sec

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Answer:

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Solving for V we get:

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6 0
3 years ago
8 POINTS AND BRAINIEST FOR CORRECT ANSWER
Fiesta28 [93]
The answer would be B. :)
8 0
3 years ago
Douglas has a segment with endpoints I(5, 2) and J(9, 10) that is divided by a point K such that IK and KJ form a 2:3 ratio. He
Rufina [12.5K]
For the answer to the question above, 
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