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3 years ago

PLEASE HELPP!! ‼️❗️

Mathematics

2 answers:

shtirl [24]3 years ago

6 0

Nejejsndndjeekewnchdje

dedylja [7]3 years ago

4 0

Answer:

infinetily many solutions because the lines are overlapping

Step-by-step explanation:

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To make 100g of jam you need 41g of strawberries, 29g of blackberries and the rest should be sugar. What is the ratio of blackbe

vladimir2022 [97]

Answer:

The ratio is 29:30

Step-by-step explanation:

First, we need to calculate the mass of sugar in the mix

That would be 100-41-29 = 100-70 = 30g

So the ratio of blackberry to sugar would be mass of the blackberry : mass of sugar

From the question, mass of blackberry = 29g while the mass of sugar = 30g

Mass of blackberry to mass of sugar = 29:30

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3 years ago

Which expression is equivalent to 5x +10y-15

diamong [38]

I think it's 5(x+2y-3)

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3 years ago

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1+ root2x + 1 = root2x + 8

hodyreva [135]

Answer:

14x 2 +9

Step-by-step explanation:

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2 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ICE Princess25 [194]

Answer:

Part a) The area of the figure is $\frac{9}{2}(4+\pi )\ cm^{2}$

Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

$A2=\pi r^{2}/2$

we have that

$r=6/2=3\ cm$

substitute

$A2=\pi (3)^{2}/2$

$A2=(9/2) \pi\ cm^{2}$

The area of the figure is equal to

$18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}$

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

$P=AB+AC+length\ CB$

we have

$AB=6\ cm$

Applying Pythagoras theorem

$AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm$

Remember that

the circumference of a semicircle is equal to

$C=\frac{1}{2}2\pi r=\pi r$

$r=6/2=3\ cm$

$C=\pi(3)$

$C=3 \pi\ cm$

The perimeter of the figure is equal to

$P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm$

Simplify

$P=3(2+2\sqrt{2}+ \pi)\ cm$

5 0

3 years ago

Please help if possible due really soon thank you so so much ❤️❤️❤️

Nataly [62]

Answer:

Step-by-step explanation:

happy holidays!!!!!!!! love you u are strong and a true buddy

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3 years ago