The answer is going to be B
The magnification of the ornament is 0.25
To calculate the magnification of the ornament, first, we need to find the image distance.
Formula:
- 1/f = u⁻¹+v⁻¹.................... Equation 1
Where:
- f = Focal length of the ornament
- u = image distance
- v = object distance.
make u the subject of the equation
- u = fv/(f+v)................ Equation 2
From the question,
Given:
Substitute these values into equation 2
- u = (12×4)/(12+4)
- u = 48/16
- u = 3 cm.
Finally, to get the magnification of the ornament, we use the formula below.
- M = u/v.................. Equation 3
Where
- M = magnification of the ornament.
Substitute these values above into equation 3
Hence, The magnification of the ornament is 0.25
Uh are u okay? G tell ur parents i-
Answer:
tex]2.898\times 10^{-7}\ \text{m}[/tex] ultraviolet region
x-ray region
Explanation:
T = Temperature
b = Constant of proportionality = 
= Wavelength
From Wein's law we have
The wavelength of the radiation will be 
and it is in the ultraviolet region.
The wavelength of the radiation will be and it is in the x-ray region.
