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3 years ago

12

Object A moves with a constant velocity of -10 m/s and object B moves with a constant velocity of 5 m/s. Which object has the la

rger speed?

1 answer:

KonstantinChe [14]3 years ago

8 0

Object A has the larger speed because speed is not a vector quantity, it is scalar. This means that directionality, or in this case the sign of the velocity, doesn’t matter.
Speed = |velocity|
Object a speed =|-10|=10 m/s
Object b speed =|5|=5 m/s

Object a is the answer.

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Calculate the centripetal force acting on a 925 kg car as it rounds an unbanked curve with a radius of 75 m at a speed of 22 m/s

igomit [66]

Since f=m(v^2/r),or fnet is equal to ma.

force = unknown
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3 years ago

If the entire population of Earth were transferred to the Moon, how far would the center of mass of the Earth-Moon-population sy

Genrish500 [490]

The question is incomplete. The complete question is :

If the entire population of Earth were transferred to the Moon, how far would the center of mass of the Earth-Moon population system move? Assume the population is 7 billion, the average human has a mass of 65 kg, and that the population is evenly distributed over both the Earth and the Moon. The mass of the Earth is 5.97×1024 kg and that of the Moon is 7.34×1022 kg. The radius of the Moon’s orbit is about 3.84×105 m.

Solution :

Given :

Mass of earth, $M_e = 5.97 \times 10^{24} \ kg$

Mass of moon, $M_m = 7.34 \times 10^{22} \ kg$

Mass of each human, $m_p =65 \ kg$

Therefore mass of total population, $M_p = 65 \times 7 \times 10^{9} \ kg$

$M_p = 4.55 \times 10^{11} \ kg$

Let the earth is at the origin of the coordinate system. Then,

Since $M_e>> M_p$

$M_m>> M_p$

Hence if we shift all the population on the moon there will be negligible change in the mass of the moon and earth. Hence there will not be any significant shift on the centre of mass. i.e.

$X_{cm} = \frac{5.97 \times 10^{24}+ 7.34 \times 10^{22} \times 3.84 \times 10^5}{5.97 \times 10^{24}+ 7.34 \times 10^{22}}$

$= 4.68 \times 10^6 \ m$

$4.68 \times 10^3 \ km$ from the earth.

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3 years ago

Convert 830kg to cg using conversion factor

Len [333]

Answer:

83000000

Explanation:

Conversion factor: 1 kg = 100000 cg

1) Centigram = Kilogram * 100000

2) Centigram = 830 * 100000

3) Centigram = 83000000

~~Hope this helps~~

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3 years ago

The periodic table is an arrangment of the chemical elements, ordered by atomic number, into families, and by doing so illustrat

olya-2409 [2.1K]

Answer:

<em><u>Option B) reactive to nonreactive</u></em>

Explanation:

<u>A) Solid to gas</u>

This might apply, because most of the gases are to the right portion of the periodic table

There are just a few elements that are gases at room temperature; a total of 11: six noble gases (group 18), two halogens (group 17), oxygen (group 16), nitrogen (group 15), and hydrogen (group 1).

Hydrogen is an exception to this trend because they are in the left part of the periodic table.

<u>B) Reactive to nonreactive</u>

The most reactive metals are in group 1 (alkali metals) and the most reactive nonmentals are in the group 18 (halogens). Hence, it is false that the from left to right the preperties go from reactive to nonreactive.

Hence, this is the one that cannot apply.

<u>C) Metal to metalloid to nonmetal</u>

It is true that the metallic character of the elements decreases from left to right; the metals are to the left, going to the right you find some metalloids, and further to the right you find the nonmetals.

Hence, this trend is correct.

<u />

<u>D) Increasing number of outer-shell electrons</u>

The number of outer-shell electrons definetly increase from left to right.

The number of electrons in neutral atoms equals the number of protons (to balance the positive and negative charges). Since, the atomic number (the number of protons) increase from left to right, the number of electrons also increase.

In a period (a row of the periodic table) the electrons add to the same outer-shell, then you will find that the number of electrons of the outer-shell increase from left to right. Hence, this is also a correct trend.

In conclusion, the only trend that does not apply is the described by the option B).

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3 years ago

Read 2 more answers

Can anyone help me ??

mash [69]

It's the second one that the answer

3 0

3 years ago