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3 years ago

A railroad car is pulled through the distance of 960 m by a train that did 578 kJ of work during this pull.

Physics

1 answer:

Wittaler [7]3 years ago

7 0

Answer:

Explanation:

The force supplied by the train can be found by using the formula

$f = \frac{w}{d} \\$

w is the workdone

d is the distance

From the question we have

$f = \frac{578000}{960} \\ = 602.083333...$

We have the final answer as

Hope this helps you

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An electron with a charge of -1.6 × 10-19 coulombs experiences a field of 1.4 × 105 newtons/coulomb. What is the magnitude of th

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Answer:

Electric force, $F=2.24\times 10^{-14}\ N$

Explanation:

It is given that,

Charge on an electron is $-1.6\times 10^{-19}\ C$

Electric field, $E=1.4\times 10^5\ N/m$

We need to find the magnitude of the electric force on this electron due to this field. The electric force is given by :

$F=qE\\\\F=1.6\times 10^{-19}\times 1.4\times 10^5\\\\F=2.24\times 10^{-14}\ N$

So, the electric force is $2.24\times 10^{-14}\ N$ .

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2 years ago

A body of mass 5.0 kg is suspended by a spring which stretches 10 cm when the mass is attached. It is then displaced downward an

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Answer:

position as a function of time is y = 0.05 × cos(9.9)t

Explanation:

given data

mass = 5 kg

length = 10 cm = 0.1 m

displaced = 5 cm

to find out

position as a function of time

solution

we will apply here equilibrium that is

mass × g = k × length

put here value and find k

k = $\frac{5*9.8}{.01}$

k = 490 N/m

and ω is

ω = $\sqrt{\frac{k}{m} }$

ω = $\sqrt{\frac{490}{5} }$

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so here position w.r.t time is

y = 0.05 × cosωt

y = 0.05 × cos(9.9)t

so position as a function of time is y = 0.05 × cos(9.9)t

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3 years ago

Which from radiation from the electromagnetic spectrum is MOST LIKELY to cause mutations in growing tissues, and should be MOST

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Answer:

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When you look at the light from distant stars you are really looking back in time explain what this means

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2 years ago

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The force of repulsion between two like–charged table tennis balls is 8.2 × 10-7 newtons. If the charge on the two objects is 6.

Allisa [31]

solution

In This question we have given ,

Charge on each ball= $q=6.7\times 10^{-9} C$

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Let distance between ball be x

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$x^2=\frac{9.0\times 10^9 Nm^2C^{-2}\times 6.7^2\times 10^{-18} C^2}{8.2\times 10^{-7}N}$

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$x=.701m$

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3 years ago

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