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Tatiana [17]
3 years ago
15

A cat starts to walk straight across a 100-meter-long field to her favorite tree. After 20 m, a dog sees the cat and chases it a

cross the field and up the tree. If the average speed of the running cat is 10 m/s, how much time did it take for the cat to get to the tree?
A. 0.8 s
B. 2 s
C. 8 s
D. 10 s
Physics
1 answer:
AleksAgata [21]3 years ago
5 0

Answer:

8 seconds, Answer choice C.

Explanation:

The information they give us about the speed of the cat, is from the point at which the dog started chasing it (that velocity being 10 m/s).

Notice that the actual distance the cat run is: 100 meters minus 20 meters (100 - 20 = 80 meters). Therefore, we have information on the distance covered by the cat (80 meters), and its speed (10 m/s), so we can use the definition of speed to find the time it took the cat to get to the tree:

speed=\frac{distance}{time} \\10 \frac{m}{s} = \frac{80\,m}{time}\\time=\frac{80}{10} s=8 \,s

Since all units for the physical quantities involved were given in the SI system,  the answer comes also in the SI units of time: "seconds"

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Match each statement with the characteristic of scientists.
Dimas [21]

Answer:

Options B, A, D, C

Explanation:

When a scientists, let's say Roberto wonders if the presence of other elements also affects the color of a flame, he can decide to prove this through a study. Therefore, in chemistry class, Roberto sees that traces of lithium makes a flame appear bright red. Subsequently, Roberto designs an experiment to test flame color in the presence of different elements and finally Roberto's friend tells him the color of a flame cannot be changed, but Roberto is still unsure.

5 0
3 years ago
Read 2 more answers
MARKING BRAINLIST | Which situation below would have the STRONGEST gravitational force between them?
maks197457 [2]

Case d) has the strongest gravitational force

Explanation:

The magnitude of the gravitational force between two objects is given by the equation:

F=G\frac{m_1 m_2}{r^2}

where :

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

a) For this pair of objects:

m1 = 10 kg

m2 = 2 kg

r = 30 km = 30,000 m

So the gravitational force is

F=(6.67\cdot 10^{-11})\frac{(10)(2)}{30000^2}=1.48\cdot 10^{-18}N

b) For this pair of objects:

m1 = 10 kg

m2 = 10 kg

r = 30 km = 30,000 m

So the gravitational force is

F=(6.67\cdot 10^{-11})\frac{(10)(10)}{30000^2}=7.41\cdot 10^{-18}N

c) For this pair of objects:

m1 = 2 kg

m2 = 2 kg

r = 10 km = 10,000 m

So the gravitational force is

F=(6.67\cdot 10^{-11})\frac{(2)(2)}{10000^2}=1.33\cdot 10^{-17}N

d) For this pair of objects:

m1 = 10 kg

m2 = 10 kg

r = 10 km = 10,000 m

So the gravitational force is

F=(6.67\cdot 10^{-11})\frac{(10)(10)}{10000^2}=6.67\cdot 10^{-17}N

Therefore, the  strongest gravitational force is in case d).

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

6 0
3 years ago
Help please, I need it
love history [14]

Answer:

1.97×10⁻²¹ J

Explanation:

Use ideal gas law to find temperature.

PV = nRT

(9 atm) (9 L) = (83.3 mol) (0.0821 L·atm/mol/K) T

T = 11.9 K

The average kinetic energy per atom is:

KE = 3/2 kT

KE = 3/2 (1.38×10⁻²³ J/K) (11.9 K)

KE = 2.46×10⁻²² J

For a mass of 5.34×10⁻²⁶ kg, the kinetic energy is:

KE = (5.34×10⁻²⁶ kg) (1 mol / 0.004 kg) (6.02×10²³ atom/mol) (2.46×10⁻²² J)

KE = 1.97×10⁻²¹ J

5 0
4 years ago
Which of the following is true concerning nuclear fusion?
Artyom0805 [142]
Choice-a is a very rubbery, imprecise, ambiguous, slippery statement. But it's probably less wrong than any of the other choices on the list.
6 0
3 years ago
What net force is required to accelerate a car at a rate of 5 m/s ^ 2 if the car has a mass of 3, 000 kg ?
Olenka [21]

Answer:

The answer is 15000kgms^-2

Explanation:

Actually here we are using the formula F=ma

3 0
3 years ago
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