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3 years ago

The vertex of this parabola is at (-3,-2). Which of the following could be its

Mathematics

1 answer:

Maslowich3 years ago

4 0

Answer:

B.y=-2(x+3)2-2

Step-by-step explanation:

A if false beacuse you have to put (-3,-2) into all of your equations

B is correct

C is false

D is also false

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I need help with this question I wasn’t sure on what to pick as the answer.

Arturiano [62]

Answer: 7 5/7 (the bottom one)

Step-by-step explanation:

30 divided by 2 = 15 (do the same to 42 and get 21)

This then creates the fraction: 15/21

Now, divide this fraction by 3 and get 5/7

Add back in the seven because you aren't dividing the whole number.

Your final answer is now 7 and 5/7 (together: 7 5/7)

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3 years ago

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MatroZZZ [7]

Answer:

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3 years ago

The net of square pyramid is shown below. What is the surface area of the pyramid?

miv72 [106K]

The surface area of that pyramid is 192 cm^2

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3 years ago

Read 2 more answers

Just do number 3 and yeah that’s it

taurus [48]

75% my dude.........

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3 years ago

Read 2 more answers

HELP MARKING BRAINLIEST EXTRA POINTS !!

Scrat [10]

Answer:

The quadrilateral is a rectangle
$Perimeter=8\sqrt{2} \,\,Unit$
$Area=6\,\,sq.unit$

Step-by-step explanation:

Given,

$A=(0,0)\\B=(1,1)\\C=(4,-2)\\D=(3,-3)$

Now,

$Slope\,\,for\,\,AB=\frac{1-0}{1-0} =1\\\\Slope\,\,for\,\,CD=\frac{-3+2}{3-4} =1\\\\Slope\,\,for\,\,AD=\frac{-3-0}{3-0} =-1\\\\Slope\,\,for\,\,BC=\frac{-2-1}{4-1} =-1\\\\So,AB||CD\,\,and\,\,AD||BC$

$AB=\sqrt{(1-0)^2+(1-0)^2}=\sqrt{2}\\BC=\sqrt{(4-1)^2+(-2-1)^2}=3\sqrt{2}\\CD=\sqrt{(3-4)^2+(-3+2)^2}=\sqrt{2}\\AD=\sqrt{(3-0)^2+(-3-0)^2}=3\sqrt{2}\\\\So,\,\,AB=CD,AD=BC\\The\,\,quadrilateral\,\,is\,\,a\,\,rectangle$

$Perimeter=2*(AB+AD)=2*(BC+CD)\\=2*(\sqrt{2}+3\sqrt{2})=8\sqrt{2} \,\,Unit$

$Area=AB*AD=BC*CD=\sqrt{2} *3\sqrt{2}=6\,\,sq.unit$

Hope you have understood this.....

ask me if you have any confusion.....

if you liked it pls mark it as the brainliest

5 0

3 years ago