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2 years ago

Very important question ☺️

Mathematics

2 answers:

mihalych1998 [28]2 years ago

5 0

Answer:

130⁰

Step-by-step explanation:

Let,

<Q = x

<R = y

So,

In ∆PQR

2x + 2y + 80 = 180(Sum of all angle in a triangle is 180⁰)

2(x + y) = 180 - 80

2(x + y) = 100

x + y = 100/2

x + y = 50

Now,

In ∆QOR

x + y + QOR = 180(Sum of all angle in a triangle is 180⁰)

50 + QOR = 180

QOR = 180 - 50

QOR = 130⁰

steposvetlana [31]2 years ago

4 0

Answer:

130° is the correct answer

∠QPR=80°

∠PQR+∠QPR+∠QRP=180°

∠PQR+∠QRP=100°

2(x+y)=100°

x+y=50°

So, in △QOR

x+y+∠QOR=180°

∴∠QOR=180°−50°

=130°

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Step-by-step explanation:

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3 years ago

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3 years ago

Find the standard form of the equation of the hyperbola satisfying the given conditions: X intercept +/- 6; foci at (-10,0) and

uysha [10]

Answer:

$\frac{x^{2}}{36} - \frac{y^{2}}{64}=1$

Step-by-step explanation:

Given an hyperbola with the following conditions:

Foci at (-10,0) and (10,0)
x-intercept +/- 6;

The following holds:

The center is midway between the foci, so the center must be at (h, k) = (0, 0).

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The center lies on the origin, so the two x-intercepts must then also be the hyperbola's vertices.

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Therefore, substituting $a^2 = 36.$ and $b^2=64$ into the standard form

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3 years ago

The perimeter of the rectangle above is:

Nonamiya [84]

Step-by-step explanation:

given,

length = 4x²

breadth/width = y²

we know,

perimeter = 2l + 2b

so,

2(4x²) + 2(y²)

→ 8x² + 2y²

option A is correct

hope this answer helps you dear...take care and may u have a great day ahead!

4 0

3 years ago

Very important question ☺️​

Very important question ☺️