Responder:
13,01 m / s
Explicación:
Paso uno:
datos dados
masa de la persona 1 m = 80 kg
velocidad de la persona 1 v = 9 m / s
masa de la persona 2 M = 55kg
velocidad de la persona 2 v =?
Segundo paso:
la expresión del impulso se da como
P = mv
para la primera persona, el impulso es
P = 80 * 9
P = 720N
Paso tres:
queremos que la segunda persona tenga el mismo impulso que la primera, por lo que la velocidad debe ser
720 = 55v
v = 720/55
v = 13,09
v = 13,01 m / s
Por lo tanto, la magnitud de la velocidad debe ser 13.01 m / s.
 
        
             
        
        
        
Answer:
F = 768 N                  
Explanation:
It is given that,
Speed of the elevator, v = 3.2 m/s
Grain drops into the car at the rate of 240 kg/min, 
We need to find the magnitude of force needed to keep the car moving constant speed. The relation between the momentum and the force is given by :


Since, the speed is constant,



F = 768 N
So, the magnitude of force need to keep the car is 768 N. Hence, this is the required solution.
 
        
             
        
        
        
A liquid requires enthalpy of vaporization to transform into vapor or gas at its boiling point.  Here the element absorbs heat from surroundings or heat source.
This energy is used in breaking the forces of attraction among the atoms and molecules of the element. The molecules get separated to higher distances. The energy is converted in to the kinetic energy of the molecules in gaseous form and into the internal energy in terms of the temperature of the gas.
        
             
        
        
        
Answer:
0° C
Explanation:
Given that
Mass of ice, m = 50g
Mass of water, m(w) = 50g
Temperature of ice, T(i) = 0° C
Temperature of water, T(w) = 80° C
Also, it is known that
Specific heat of water, c = 1 cal/g/°C
Latent heat of ice, L(w) = 89 cal/g
Let us assume T to be the final temperature of mixture.
This makes the energy balance equation:
Heat gained by ice to change itself into water + heat gained by melted ice(water) to raise its temperature at T° C = heat lost by water to reach at T° C
m(i).L(i) + m(i).c(w)[T - 0] = m(w).c(w)[80 - T], on substituting, we have
50 * 80 + 50 * 1(T - 0) = 50 * 1(80 - T) 
4000 + 50T = 4000 - 50T
0 = 100 T
T = 0° C
Thus, the final temperature is 0° C
 
        
             
        
        
        
Answer:
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