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zmey [24]
3 years ago
7

11. A 2.5-kg block slides down a 25o inclined plane with a constant acceleration. The block starts from rest at the top. At the

bottom, its velocity reaches 0.65 m/s. The length of the incline is 1.6m. a) What is the acceleration of the block?
b) What is the coefficient of friction between the plane and the block?
c) Does the result of either (a) or (b) depend on the mass of the block?
Physics
1 answer:
erastovalidia [21]3 years ago
5 0

Answer:

Explanation:

Given

mass of Block m=2.5 kg

velocity at bottom v=0.65 m/s

Length of Ramp L=1.6 m

inclination \theta =25^{\circ}

using v^2-u^2=2 as

where a=acceleration

s=displacement

v=final velocity

u=initial velocity

0.65^2-0=2\times a\times 1.6

a=0.132 m/s^2

(b)Block is moving downward with constant acceleration is given by

F_{net}=mg\sin \theta -\mu mg\cos \theta

a=g\sin \theta -\mu g\cos \theta

0.132=g(\sin 25-\mu \cos 25)

\mu \cdot 0.906=0.4360

\mu =\frac{0.4360}{0.906}

\mu =0.481

Result will remain same irrespective of mass

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Una persona de 80 kg de masa corre a una velocidad cuya magnitud es de 9m/s. Cual es la magnitud de la cantidad de movimiento? Q
natka813 [3]

Responder:

13,01 m / s

Explicación:

Paso uno:

datos dados

masa de la persona 1 m = 80 kg

velocidad de la persona 1 v = 9 m / s

masa de la persona 2 M = 55kg

velocidad de la persona 2 v =?

Segundo paso:

la expresión del impulso se da como

P = mv

para la primera persona, el impulso es

P = 80 * 9

P = 720N

Paso tres:

queremos que la segunda persona tenga el mismo impulso que la primera, por lo que la velocidad debe ser

720 = 55v

v = 720/55

v = 13,09

v = 13,01 m / s

Por lo tanto, la magnitud de la velocidad debe ser 13.01 m / s.

4 0
3 years ago
A railroad car moves under a grain elevator at a constant speed of 3.20 m/s. Grain drops into the car at the rate of 240 kg/min.
dedylja [7]

Answer:

F = 768 N                  

Explanation:

It is given that,

Speed of the elevator, v = 3.2 m/s

Grain drops into the car at the rate of 240 kg/min, \dfrac{dm}{dt}=240\ kg/min = 4\ kg/s

We need to find the magnitude of force needed to keep the car moving constant speed. The relation between the momentum and the force is given by :

F=\dfrac{dp}{dt}

F=m\dfrac{dv}{dt}+v\dfrac{dm}{dt}

Since, the speed is constant,

F=m\dfrac{dv}{dt}

F=v\dfrac{dm}{dt}

F=3.2\times 240

F = 768 N

So, the magnitude of force need to keep the car is 768 N. Hence, this is the required solution.

5 0
3 years ago
Explain the role of energy in changes <br> of state.
slava [35]
A liquid requires enthalpy of vaporization to transform into vapor or gas at its boiling point.  Here the element absorbs heat from surroundings or heat source.

This energy is used in breaking the forces of attraction among the atoms and molecules of the element. The molecules get separated to higher distances. The energy is converted in to the kinetic energy of the molecules in gaseous form and into the internal energy in terms of the temperature of the gas.


3 0
3 years ago
50g of ice at 0°C is mixed with 50g of water at 80°C, what will be the final temperature of a mixture in
xxTIMURxx [149]

Answer:

0° C

Explanation:

Given that

Mass of ice, m = 50g

Mass of water, m(w) = 50g

Temperature of ice, T(i) = 0° C

Temperature of water, T(w) = 80° C

Also, it is known that

Specific heat of water, c = 1 cal/g/°C

Latent heat of ice, L(w) = 89 cal/g

Let us assume T to be the final temperature of mixture.

This makes the energy balance equation:

Heat gained by ice to change itself into water + heat gained by melted ice(water) to raise its temperature at T° C = heat lost by water to reach at T° C

m(i).L(i) + m(i).c(w)[T - 0] = m(w).c(w)[80 - T], on substituting, we have

50 * 80 + 50 * 1(T - 0) = 50 * 1(80 - T)

4000 + 50T = 4000 - 50T

0 = 100 T

T = 0° C

Thus, the final temperature is 0° C

3 0
3 years ago
Help<br> help <br> help<br> plssss
Flauer [41]

Answer:

sorry i don't no

i promise i will help you later

now i am also in trouble now

nobody helps me

4 0
2 years ago
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