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zmey [24]
3 years ago
7

11. A 2.5-kg block slides down a 25o inclined plane with a constant acceleration. The block starts from rest at the top. At the

bottom, its velocity reaches 0.65 m/s. The length of the incline is 1.6m. a) What is the acceleration of the block?
b) What is the coefficient of friction between the plane and the block?
c) Does the result of either (a) or (b) depend on the mass of the block?
Physics
1 answer:
erastovalidia [21]3 years ago
5 0

Answer:

Explanation:

Given

mass of Block m=2.5 kg

velocity at bottom v=0.65 m/s

Length of Ramp L=1.6 m

inclination \theta =25^{\circ}

using v^2-u^2=2 as

where a=acceleration

s=displacement

v=final velocity

u=initial velocity

0.65^2-0=2\times a\times 1.6

a=0.132 m/s^2

(b)Block is moving downward with constant acceleration is given by

F_{net}=mg\sin \theta -\mu mg\cos \theta

a=g\sin \theta -\mu g\cos \theta

0.132=g(\sin 25-\mu \cos 25)

\mu \cdot 0.906=0.4360

\mu =\frac{0.4360}{0.906}

\mu =0.481

Result will remain same irrespective of mass

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Answer:

r₂ = 0.316 m

Explanation:

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            β = 10 log \frac{I}{I_o}

let's write this expression for our case

           β₁ = 10 log \frac{I_1}{I_o}

           β₂ = 10 log \frac{I_2}{I_o}

           

          β₂ -β₁ = 10 ( log \frac{I_2}{I_o} - log \frac{I_1}{I_o})

          β₂ - β₁ = 10 log \frac{I_2}{I_1}

          log \frac{I_2}{I_1} = \frac{60 - 20}{10} = 3

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having the relationship between the intensities, we can use the definition of intensity which is the power per unit area

           I = P / A

           P = I A

the area is of a sphere

          A = 4π r²

           

the power of the sound does not change, so we can write it for the two points

          P =  I₁ A₁ =  I₂ A₂

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we substitute the ratio of intensities

          I₁ r₁² = (10³ I₁ ) r₂²

         r₁² = 10³ r₂²

         

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          r₂ = \frac{10.0}{\sqrt{10^3} }

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27b. You're in an airplane that flies horizontally with speed 1000 km/h (280 m/s) when an engine falls off. Ignore air resistanc
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Answer:

8400m

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The engine that falls off would have the same constant horizontal velocity as the airplane's when if falls off if we ignore air resistance. So it would have a horizontal velocity of 280m/s for 30seconds before it hits the ground.

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Jake is in chemistry class. He makes a list of the chemicals his instructor described and the properties of each.
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