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klasskru [66]
3 years ago
14

2. A portion of the body receives 0.15 mGy from radiation with a quality factor Q = 6 and 0.22 mGy from radiation with Q = 10. (

a) What is the total dose? (b) What is the total dose equivalent?
Physics
1 answer:
DiKsa [7]3 years ago
7 0

Answer with Explanation:

We are given that

D_1=0.15mGy

D_2=0.22mGy

Q_1=6

Q_2=10

a.We have to find the total dose

Total dose=D=D_1+D_2

Using the formula then, we get

D=0.15+0.22

D=0.37mGy

b.We have to find the total dose equivalent

Total dose equivalent=H=D_1Q_1+D_2Q_2

Using the formula

H=0.15(6)+0.22(10)

H=3.1mSv

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8 0
3 years ago
A 9.0-V battery (with nonzero resistance) and switch are connected in series across the primary coil of a transformer. The secon
qwelly [4]

Answer:

N₂ / N₁ = 13.3

Explanation:

A transformer is a system that induces a voltage in the secondary due to the variation of voltage in the primary, the ratio of voltages is determined by the expression

           ΔV₂ = N₂ /N₁  ΔV₁

where ΔV₂ and ΔV₁ are the voltage in the secondary and primary respectively and N is the number of windings on each side.

In this case, they indicate that the primary voltage is 9.0 V and the secondary voltage is 120 V

therefore we calculate the winding ratio

         ΔV₂ /ΔV₁ = N₂ / N₁

         N₂ / N₁ = 120/9

         N₂ / N₁ = 13.3

s good clarify that in transformers the voltage must be alternating (AC)

3 0
3 years ago
What are the general characteristics of a solid?
Arisa [49]
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4 0
3 years ago
An object possessing an excess of 6.0x10^6 electrons has a net charge of
guajiro [1.7K]
A single electron has a charge of
e=-1.6 \cdot 10^{19}C
Therefore, if we have an excess of N=6.0\cdot10^6 electrons, the total net charge will be the product between the charge of a single electron and the total number of electrons in excess:
Q=Ne=(6.0\cdot10^6)(-1.6 \cdot 10^{-19}C)=9.6 \cdot 10^{-13}C
7 0
3 years ago
An electric field of 1139 V/m is applied to a section of silver of uniform cross section. Find the resulting current density if
N76 [4]

Answer:

So, you're going to need the equation ρ = ρo [1 + α(T-To)]  

1.59x10^-8 ohms*m is your ρo because that is measured at your reference temperature (To), 20◦C. T is your 6◦C and α is 0.0038(◦C)−1. So, using that you solve for ρ. If you keep up with the units though, you notice it comes out to be ohms*m and that isn't what you want.  

So, the next equation you need is J=σE where E is your electric field (3026 V/m) and σ is the electrical conductivity which is the inverse of your answer you got in the previous equation. So find the inverse of that answer and multiply it by your electric field and that will give you the current density.  

I hope this helps!

Explanation:

8 0
3 years ago
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