Answer: - 452.088joule
Explanation:
Given the following :
Mass of water = 12g
Change in temperature(Dt) = (11 - 20)°C = - 9°C
Specific heats capacity of water(c) = 4.186j/g°C
Q = mcDt
Where Q = quantity of heat
Q = 12g × 4.186j/g°C × - 9°C
Q = - 452.088joule
Answer:
≈19.144°C.
Explanation:
all the details are in the attachment.
Note, that c₁, m₁, t₁ are the parameters of the sample of brass; c₂, m₂ and t₂ are the parameters of the sample of water.
P.S. change the provided design according Your requirements.
Answer:
No, the volume don't affect the potential energy.
Explanation:
The volume does not affect the potential energy, as this energy depends on the mass and elevation of the body relative to the reference point. This analysis can be easily seen in the equation expressing potential energy
![E_{p} =m*g*h\\where:\\m=mass[kg]\\g=gravity[m/^2]\\h=elevation[m]](https://tex.z-dn.net/?f=E_%7Bp%7D%20%3Dm%2Ag%2Ah%5C%5Cwhere%3A%5C%5Cm%3Dmass%5Bkg%5D%5C%5Cg%3Dgravity%5Bm%2F%5E2%5D%5C%5Ch%3Delevation%5Bm%5D)