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sammy [17]
3 years ago
7

A sample of a gas has a pressure of 248mm Hg when the volume is 1.05L. What is the pressure of the gas when the volume is 3.98L?

Chemistry
2 answers:
ozzi3 years ago
8 0
P1V1 = P2V2
Convert 248mm Hg to atm
248/760 = 0.326 atm
(0.326 atm • 1.05L) / 3.98L = 0.0861 atm
slamgirl [31]3 years ago
6 0

So Boyle's Law equation is going to be used to solve this problem.

Boyle's Law: (P1)(V1)=(P2)(V2)

So, based on the question. Let's first note down what is given.

P1= 248mm Hg

V1= 1.05L

P2= ? (<-- What we are going to be solving for)

V2= 3.98L

Based on what we know, we can just simply plug it into the equation.

So...

1. (248 mmHg) (1.05L) = (P2) (3.98L)

2. (248 mm Hg) (1.05L)

   -----------------------------    =     P2

        (3.98L)

3. P2 = 65.4 mm Hg is your answer

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3 years ago
A. Convert the mass of the Salt weighed out to fg.
omeli [17]

Answer:

6.564×10¹⁶ fg.

Explanation:

The following data were obtained from the question:

Mass of beaker = 76.9 g

Mass of beaker + salt = 142.54 g

Mass of salt in fg =?

Next, we shall determine the mass of the salt in grams (g). This can be obtained as follow:

Mass of beaker = 76.9 g

Mass of beaker + salt = 142.54 g

Mass of salt =?

Mass of salt = (Mass of beaker + salt) – (Mass of beaker)

Mass of salt = 142.54 – 76.9

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1 g = 1×10¹⁵ fg

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65.64 g = 65.64 g × 1×10¹⁵ fg / 1g

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Therefore, the mass of the salt is 6.564×10¹⁶ fg.

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