All categories

3 years ago

A sample of a gas has a pressure of 248mm Hg when the volume is 1.05L. What is the pressure of the gas when the volume is 3.98L?

Chemistry

2 answers:

ozzi3 years ago

8 0

P1V1 = P2V2
Convert 248mm Hg to atm
248/760 = 0.326 atm
(0.326 atm • 1.05L) / 3.98L = 0.0861 atm

slamgirl [31]3 years ago

6 0

So Boyle's Law equation is going to be used to solve this problem.

Boyle's Law: (P1)(V1)=(P2)(V2)

So, based on the question. Let's first note down what is given.

P1= 248mm Hg

V1= 1.05L

P2= ? (<-- What we are going to be solving for)

V2= 3.98L

Based on what we know, we can just simply plug it into the equation.

So...

1. (248 mmHg) (1.05L) = (P2) (3.98L)

2. (248 mm Hg) (1.05L)

----------------------------- = P2

(3.98L)

3. P2 = 65.4 mm Hg is your answer

You might be interested in

En el laboratorio, un vaso precipitado vacío tiene una masa de 0,50 kg. Este vaso se llena con 300 cm3 de una solución saturada

faust18 [17]

Answer:

Density = 0.0007667 Kg/cm³

Explanation:

Given the following data;

Mass of empty beaker = 0.50 kg

Volume of solution = 300 cm³

Mass of glass+solution = 730 g

To find the density of the solution in the glass;

First of all, we would convert the value in grams to kilograms.

Conversion:

1000 grams = 1 kg

730 = X kg

Cross-multiplying, we have;

X = 730/1000 = 0.73 kg

Next, we would determine the mass of the solution.

Mass of solution = Mass of glass+solution - Mass of empty beaker

Mass of solution = 0.73 - 0.50

Mass of solution = 0.23 kg

Lastly, we would solve for the density of the solution;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the formula;

$Density = \frac {mass}{volume}$

Substituting into the formula, we have;

$Density = \frac {0.23}{300}$

Density = 0.0007667 Kg/cm³

4 0

2 years ago

Identify the power of ten that defines each of these prefixes. Input your answers as 10 x where x is the power of ten. nano- ___

Gemiola [76]

Answer: The quantity of every prefix is written below as a power of ten.

Explanation:

In the metric system of measurement, the name of multiples and subdivision of any unit is done by combining the name of the unit with the prefixes.

For Example: deka, hecto and kilo means 10, 100 and 1000 respectively. Deci, centi and milli means one-tenth, one-hundredth, and one-thousandth respectively.

The quantity of these prefixes are written as the power of 10.

For the given prefixes:

Nano: The quantity will be $10^{-9}$

Kilo: The quantity will be $10^3$

Centi: The quantity will be $10^{-2}$

Micro: The quantity will be $10^{-6}$

Milli: The quantity will be $10^{-3}$

Mega: The quantity will be $10^6$

Hence, the quantity of every prefix is written above as a power of ten.

7 0

3 years ago

If 5 mol of oxygen gas effuses through an opening in 10 seconds, how long will it take for the same amount of hydrogen gas to ef

andrezito [222]

Answer:

Explanation:

Recall the law of effusion:

$\displaystyle \frac{r_1}{r_2} = \sqrt{ \frac{\mathcal{M}_2}{\mathcal{M}_1} }$

Because 5 mol of oxygen was effused in 10 seconds, the rate is 0.5 mol/s.

Let the rate of oxygen be r₁ and the rate of hydrogen be r₂.

The molecular weight of oxygen gas is 32.00 g/mol and the molecular weight of hydrogen gas is 2.02 g/mol.

Substitute and solve for r₂:

$\displaystyle \begin{aligned} \frac{(0.5\text{ mol/s})}{r_2} & = \sqrt{\frac{(2.02\text{ g/mol})}{(32.00\text{ g/mol})}} \\ \\ r_2 & = \frac{0.5\text{ mol/s}}{\sqrt{\dfrac{(2.02\text{ g/mol})}{(32.00\text{ g/mol})}}} \\ \\ & = 2.0\text{ mol/s}\end{aligned}$

Because there are 5 moles of hydrogen gas:

$\displaystyle 5.0\text{ mol} \cdot \frac{1\text{ s}}{2.0\text{ mol}} = 2.5\text{ s}$

In conclusion, it will take about 2.5 seconds for the hydrogen gas to effuse.

Check: Because hydrogen gas is lighter than oxygen gas, we expect that hydrogen gas will effuse quicker than oxygen gas.

6 0

2 years ago

Enter the chemical formula of a binary molecular compound of hydrogen and a Group 4A element that can reasonably be expected to

irakobra [83]

Answer: GeH4 (Germanium(IV) Hydride)

Explanation:

A Binary molecular compound Hydrogen and a Group 4A element which is more more acidic than SiH4 in aqueous solution is GeH4.

The pKa of GeH4;

= 25

Whilst that of SiH4

= 35

The lesser the pKa the higher the Ka which means more acidic.

6 0

2 years ago

Which of the following is NOT true regarding Rutherford's Gold Foil experiment?

erastova [34]

Answer:

The area around the nucleus must be of low mass.

Explanation:

Rutherford`s experiment showed that there are some positive charges in the center of the atoms, and because they are all together, they will give a great mass to the atom.

It was quite different from Thomson`s experiment, in which it was thought that the negative charges were mixed with the positive charges, around the atom (like a Pudding Model). In Rutherford`s experiment, because the direction of beta particles, it was the prediction of the positive nucleus.

Hope this info is useful.

8 0

3 years ago