Answer:
a)
, b) 
Explanation:
a) According to the First Law of Thermodinamics, the system is not reporting any work, mass or heat interactions. Besides, let consider that such box is rigid and, therefore, heat contained inside is the consequence of internal energy.

The internal energy for a monoatomic ideal gas is:

Let assume that cubical box contains just one kilomole of monoatomic gas. Then, the temperature is determined from the Equation of State for Ideal Gases:



The thermal energy contained by the gas is:


b) The physical model for the cat is constructed from Work-Energy Theorem:

The speed of the cat is obtained by isolating the respective variable and the replacement of every known variable by numerical values:



Answer:
: carbon tetrabromide
Explanation:
is a covalent compound because in this compound the sharing of electrons takes place between carbon and bromine. Both the elements are non-metals. Hence, it will form covalent bond.
The naming of covalent compound is given by:
1. The less electronegative element is written first.
2. The more electronegative element is written second. Then a suffix is added with it. The suffix added is '-ide'.
3. If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on.
Hence, the correct name for
is carbon tetrabromide.
Answer:
Is there a multiple choice or select all that apply? I would say Potassium (K) or Sodium (Na)
Explanation:
Answer:
So wavelength in nm will be
Explanation:
We have given that the energy = 207 KJ/mol 
Speed of light 
Plank's constant 
According to plank's rule energy of the photon is given by



So wavelength in nm will be 
Answer:
When balloon moves in the downward direction two forces acts on it.
i) Force exerted by air in the upward direction
ii) Weight
According to newton’s second law of motion:
Sum of forces = Ma
W – F = Ma
Mg – F = Ma …….. (i)
when some of the mass m is dropped and balloon is moving in upward direction with acceleration a/2 then,
F – W = (M-m)a/2
F – (M-m)g = (M-m)a/2
F – Mg + mg = Ma/2 – ma/2 ….. (ii)
Adding equation (i) and (ii)
mg = M(3a/2) – ma/2
m(g + a/2) = M(3a/2)
m = M(3a/2)/(g + a/2)