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Vadim26 [7]
3 years ago
12

Juan is comparing the brightness of two lightbulbs. Which SI unit should he use?

Physics
1 answer:
My name is Ann [436]3 years ago
5 0
You will use candela for comparing.
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when in object moves stop moving changes speed or changes direction how do scientist describe that condition?
Kruka [31]

im taking test rn nd this question was on there, im saying unbalanced force, if it not correct i will put right answer, but im pretty sure the answer is unblanced

6 0
3 years ago
Read 2 more answers
As your hand moves back and forth to generate longitudinal pulses in a spiral spring, your hand completes 2.91 back-and-forth cy
Lapatulllka [165]

Answer:

Wavelength, \lambda=0.011\ m

Explanation:

Given that,

Number of cycles in a spiral spring is 2.91 in every 3.67 s

The velocity of the pulse in the spring is 0.925 cm/s, v = 0.00925 m/s

To find,

Wavelength

Solution,

Number of cycles per unit time is called frequency of a wave. The frequency of the longitudinal pulse is,

f=\dfrac{2.91}{3.67}=0.79\ Hz

The wavelength of a wave is given by :

\lambda=\dfrac{v}{f}

\lambda=\dfrac{0.00925\ m/s}{0.79\ Hz}

\lambda=0.011\ m

So, the wavelength of the longitudinal pulse is 0.011 meters. Hence, this is the required solution.

8 0
3 years ago
Which one is having lesser ressistance. a 60w bulb or a 40w bulb?
Ivan
Power dissipation = (voltage across the component)² / (resistance of the component)

Since the resistance is in the denominator of the fraction in this formula for the
quantity of power dissipated, you can see that when the supply voltage is constant,
the smaller resistance dissipates more power.

So the <u>60w bulb</u> has lower resistance than the 40w bulb.
8 0
3 years ago
An insect 5.00 mm tall is placed 20.0 cm to the left of a thin planoconvex lens. The left surface of this lens is flat, the righ
jenyasd209 [6]

Answer:

a) i = -9.63 cm ,    h ’= .0.24075 cm   erect

b)  i = 259.74 cm ,

Explanation:

For this exercise let's start by finding the focal length of the lens

               1 / f = (n-1) (1 / R₁ - 1 / R₂)

                1 / f = (1.70 -1)) 1 / ∞ - 1/13)

                1 / f = 0.0538

                 f = - 18.57 cm

Now we can use the constructor equation

             1 / f = 1 / o + 1 / i

             1 / i = 1 / f - 1 / o

              1 / i = -1 / 18.57 -1/20

               1 / i = -0.1038 cm

               I = -9.63 cm

For the height of the

image let's use magnification

                 m = h '/ h = - i / o

                  h ’= -h i / o

                  h ’= - 0.5 (-9.63) / 20

                  h ’= .0.24075 cm

b) we invert the lens

The focal length is

             1 / f = (1.70 -1) (1/13 - 1 / int)

              1 / f = 0.0538

             f = 18.57 cm

             1 / i = 1 / f -1 / o

             1 / I = 1 / 18.57 - 1/20

             1 / I = 3.85 10-3

             i = 259.74 cm

     

            h ’= - 0.5 259.74 / 20

             h ’= 6.4935 cm

7 0
3 years ago
Select all the wave properties that can change how we perceive light waves.amplitudeamplitudecrestscreststimetimefrequency
ASHA 777 [7]

The properties that change how we perceive light waves are the following:

The amplitude of the light wave changes the brightness of light relative to other light waves of the same wavelenghth.

The frequency of the light wave changes the color and the type of the light wave.

6 0
1 year ago
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