Answer:
a) No
B) Yes
Step-by-step explanation:
Calculating the p-value, we have;
z = (p-bar) -p/√(p(1-p)/n)
But p-bar = 365/500
= 0.73
Therefore,
z = 0.73 -0.69/√0.69(1-0.69)/500
= 0.04/√0.2139/500
= 0.04/√0.0004278
= 0.04/0.02068
= 1.93
p-value = p(z ≥1.93) = 0.0268
(a) Can you conclude that the percentage of emails that are spam is greater than 69% ?
No, because the p- value is greater than α. That is p-value⊃ 0.01
(b) Can you conclude that the percentage of emails that are spam is greater than 69%
Yes, since p-value ∠ 0.05