Question

Solve a triangle with a=32, b=38, and c=46.

Answer 1

Answer:

P=116

a Side

b Base

c Side

γ

c

a

h

b

b

h

b

h

b

c

γ

a

b

a

c

b

γ

P

c

γ

a

b

A

Invalid input: make surea+b>c

Invalid input: make surea+c>b

Invalid input: make sureb+c>a

Unit Conversion:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

we have a triangle with

 a=32, b=38, and c=46

We can use the cosine rule to find the angles

It is

$cos A =\frac{b^2+c^2-a^2}{2bc}$

so plugging all the values we get

$cos A =\frac{38^2+46^2-32^2}{2.38.46}$

$cos A =\frac{317}{437}$

A= 43.5

Now for angle B , the formula is

$cos B= \frac{a^2+c^2-b^2}{2ac}$

plugging all the vaues again we get

$cos B= \frac{32^2+46^2-38^2}{2.32.46}$

$cos B= \frac{53}{92}$

B= 54.8

Now since for a triangle A+B+C =180

so C = 180 - 43.5- 54.8

C=81.7

option a