Group 'em together
a
b
−
a
+
1
−
b
a
b
−
a
=
a
(
b
−
1
)
Notice that there will be a 1 as without it it'll simply be ab
1
−
b
=
1
(
1
−
b
)
Notice that it doesn't match with the upper one... so we'll change the signs
1
(
1
−
b
)
=
−
1
(
b−
1
)
(try to multiply them now!!
Jot them down in one expression
a
(
b
−
1
)
−
1
(
b
−
1
)
You get!!!!!!
(
a
−
1
)
(
b
−
1
)
550 sq m
Step-by-step explanation:
Step 1 :
The length of the first cross road the park is 70 m
The width of the first cross road the park is 5 m
So its area is 70 * 5 = 350 sq m
Step 2 :
The length of the second cross road the park is 45 m
The width of the width cross road the park is 5 m
So its area is 45 * 5 = 225 sq m
Step 3 :
The 2 cross roads intersect in the middle at an area of 5 * 5 = 25 sq m
This area is included in the computation of the area of both the cross roads and hence we need to subtract this area from the sum of the area of both the cross roads to obtain the actual area of cross roads in the park
So we have
the area of the cross roads inside the park = 350 + 225 - 25 = 550 sq m
For this case we have the following difference equation:

Applying separable variables we have:

Integrating both sides we have:

applying exponential to both sides:

For y (1) = 1 we have:

Thus, the particular solution is:

Whose domain is all real.
Answer: y = 0.2 * exp ((3/2) x ^ 2) Domain: all real numbers
Answer:
IT is not
Step-by-step explanation:
Let's replace. If it's a solution, it means that BOTH equations has to be true.

Now, the second equations seems good -
indeed.
First alas isn't. RHS is 142, which is totally not the same as -10.