Earths atmosphere heats up polars melt
Answer:
The velocity at the ground is <u>63.25 m/s</u> and time taken is <u>6.325 s.</u>
Explanation:
Given:
As the object is released, the initial velocity is, 
Displacement of the object is, 
To find:
Velocity at the bottom, 
Time to reach the bottom, 
The acceleration of the object is due to gravity and hence equal to 
Now, using the following equation of motion:

Now, using the equation of motion relating time and velocity:

Therefore, the velocity at the ground is 63.25 m/s and time taken is 6.325 s.
Answer:
v=115 m/s
or
v=414 km/h
Explanation:
Given data

To find
Terminal velocity (in meters per second and kilometers per hour)
Solution
At terminal speed the weight equal the drag force

For speed in km/h(kilometers per hour)
To convert m/s to km/h you need to multiply the speed value by 3.6
Answer:
2.286 km/s²
Explanation:
Since acceleration a = (v - u)/t where u = initial horizontal velocity of ball = 0 m/s (since it starts from rest), v = final horizontal velocity of ball at serve = 73.14 m/s and t = time taken for serve = 32.0 ms = 0.032 s
Substituting the values of the variables into the equation, we have
a = (v - u)/t
a = (73.14 m/s - 0 m/s)/0.032 s
a = 73.14 m/s/0.032 s
a = 2285.625 m/s²
a = 2.285625 km/s²
a ≅ 2.286 km/s²
So, the x - component of the ball's acceleration during the serve is 2.286 km/s²