What effect does a doubling of the mass have upon the acceleration of the object
1 answer:
Hello there!
Your question can be answered using the Newton's Secon Law of Motion:
This Law says that the forces on an object are equal to the product of its mass (m) and acceleration (a):
If we clear this equation for acceleration, we'll see that:
So, studying this equation, we'll see that acceleration is inversely proportional to mass, thus, assuming that the force remains constant, doubling the mass will decrease the acceleration of the object by half.
Your question can be answered using the Newton's Secon Law of Motion:
This Law says that the forces on an object are equal to the product of its mass (m) and acceleration (a):
If we clear this equation for acceleration, we'll see that:
So, studying this equation, we'll see that acceleration is inversely proportional to mass, thus, assuming that the force remains constant, doubling the mass will decrease the acceleration of the object by half.
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Answer:
1408.685 KN/C
Explanation:
Given:
R = 0.45 m
σ = 175 μC/m²
P is located a distance a = 0.75 m
k = 8.99*10^9
- The Electric Field Strength E of a uniformly solid disk of charge at distance a perpendicular to disk is given by:
part a)
Electric Field strength at point P: a = 0.75 m
part b)
Since, R >> a, we can approximate a / R = 0 ,
Hence, E simplified relation becomes:
E = σ / 2*e_o
part c)
Since, a >> R, we can approximate. that the uniform disc of charge becomes a single point charge:
Electric Field strength due to point charge is:
E = k*δ*pi*R^2 / a^2
Since, R << a, Surface area = δ*pi
Hence,
E = (k*δ*pi/a^2)