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statuscvo [17]
2 years ago
7

A ball of mass 6 kg is moving to the right with a velocity of 4 m/s when it strikes a 12 kg green block moving to the left at 5

m/s. The blocks experience a Perfectly Inelastic Collision, solve for the following:
a. Momentum Before the Collision
b. Momentum After the Collision
c. Velocity of both masses after the collision.
Physics
1 answer:
Marat540 [252]2 years ago
3 0

Answer:

Velocity of both masses after the collisio

Explanation:

Hope it will help

<h2><em><u>Brainlists please</u></em></h2>
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How much heat is removed from 60 grams of steam at 100 °C to change it to 60 grams
Harrizon [31]

Answer:

45200J

Explanation:

Given parameters:

Heat of vaporization of water  = 2260J/g

Mass of steam = 20g

Temperature = 100°C

Unknown:

Energy released during the condensation  = ?

Solution:

This change is a phase change and there is no change in temperature

To find the amount of heat released;

         H  = mL

m is the mass

L is the latent heat of vaporization

Insert the parameters and solve;

         H  = 20g x 2260J/g

          H = 45200J

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2 years ago
A farmer mated two ducks. They produced three offspring. Two of the offspring were then selected to mate with each other because
cestrela7 [59]

it's called inbreeding


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3 years ago
A particle of charge Q is fixed at the origin of an xy coordinate system. At t = 0 a particle (m = 0.727 g, q = 2.73 µC is locat
Montano1993 [528]

Answer:

Q = 12.466μC

Explanation:

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Solving for Q:

Q = \frac{m*V^{2}*r}{K*q}

Taking special care of all units, we can calculate the value of the charge:

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3 years ago
You read in a science magazine that on the Moon, the speed of a shell leaving the barrel of a modern tank is enough to put the s
olga_2 [115]

To solve this problem we will use the definition of the kinematic equations of centrifugal motion, using the constants of the gravitational acceleration of the moon and the radius of this star.

Centrifugal acceleration is determined by

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If we rearrange the function to find the speed we will have to

v = \sqrt{ar}

v = \sqrt{1.6(1.74*10^6)}

v = 1.7km/s

The speed for this to happen is 1.7km/s

3 0
3 years ago
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Korvikt [17]

Answer:

In a third class lever, the effort is located between the load and the fulcrum. ... If the fulcrum is closer to the effort, then the load will move a greater distance. A pair of tweezers, swinging a baseball bat or using your arm to lift something are examples of third class levers.

Explanation:

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