1. Magnetic properties of a substance depends on the structure of its valence electrons. It has something to do with orbitals so I suggest you study about molecular geometry of a compound/substance firstIt's the way a substance's atoms fit together, being pulled and pushed from all sides equally. exists in metallic bonds <span>if a substance is said to be magnetic, it is simply attracted by a magnet. if it is paramagnetic, it is repelled by a magnet.
2.</span>The magnetic field will be perpendicular to the electric field and vice versa<span>
An electric field is the area which surrounds an electric charge within which it is capable of exerting a perceptible force on another electric charge.
A magnetic field is the area of force surrounding a magnetic pole, or a current flowing through a conductor, in which there is a magnetic flux. A magnetic field can be produced when an electric current is passed through an electric circuit wound in a helix or solenoid.
The relationship that exists between an electric field and a magnetic field is one of electromagnetic interaction as a consequence of associating elementary particles.
The electrostatic force between charged particles is an example of this relationship.</span>
Answer:
<em>D.) state of matter</em>
Explanation:
it can undergo chemical but not nuclear.
I disagree with that opinion, and I have solid Physics to back me up.
The forces of gravity are always equal in both directions. The sun pulls the Earth with exactly the same force with which the Earth pulls the sun.
It may seem weird, but your weight on Earth is exactly the same as the Earth's weight on you. For the same reason.
Answer:
The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C, but the direction is still to the right.
Explanation:
From coulomb's law, F = Eq
Thus,
F = E₁q₁
F = E₂q₂
Then
E₂q₂ = E₁q₁
where;
E₂ is the external electric field due to second test charge = ?
E₁ is the external electric field due to first test charge = 4 x 10⁶ N/C
q₁ is the first test charge = 13 mC
q₂ is the second test charge = 23 mC
Substitute in these values in the equation above and calculate E₂.
The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C when 13 mC test charge is replaced with another test charge of 23 mC.
However, the direction of the external field is still to the right.
Answer:
Amount of Energy transferred 
Explanation:
Given:
Initial volume=V
Initial pressure=P
Final volume=2V
Final pressure=3P
Now w know that the Energy transferred in constant pressure pressure is given by
Now the Energy transferred in constant volume process is given by
The total Energy transferred is given by
