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IgorLugansk [536]
3 years ago
13

Can someone please help if you can you are amazing and awesome

Mathematics
1 answer:
Ainat [17]3 years ago
4 0

Answer:

domain(-4,6) and range(-1, 8)

Step-by-step explanation:

domain is an imput on x axis, and range on y

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PLEASE HURRY
mina [271]

Answer:

X ≥ 3

Step-by-step explanation:

Let the number of grapes you'll buy be X, you need to buy at leaF 3 pounds so:

X ≥ 3

Answered by Gauthmath

5 0
3 years ago
A rectangle has a height of 7 and a width of a^4+5a^2+4a .
boyakko [2]

Answer:

  7a^4 +35a^2 +28a

Step-by-step explanation:

Area is the product of height and width:

  area = height × width

  = 7 × (a^4 +5a^2 +4a)

  area = 7a^4 +35a^2 +28a . . . . . . use the distributive property

5 0
3 years ago
Read 2 more answers
The 4 problems distributive property thanks
n200080 [17]
Looks like all you have to do it multiply the numbers together; there is no application of the Distributive Property to these problems.
7 0
3 years ago
8th grade math urgent need help
Rainbow [258]

Answer:

p > 4

Step-by-step explanation:

your welcome

7 0
3 years ago
Read 2 more answers
In triangle abc, m of acb = 90, cd is perpendicular to ab , m of acd is 60. and bd is 5 cm. find ad
weeeeeb [17]

Let us draw a picture to make the things more clear.

Attached is the image.

We have been given that

\angle acd = 60 ^{\circ}

Therefore, we have

\angle dcb =90- 60= 30 ^{\circ}

Now, in triangle bcd, we have

\tan30 = \frac{5}{cd}\\
\\
\frac{1}{\sqrt 3}=\frac{5}{cd}\\
\\
cd=5\sqrt 3

Now, in triangle acb, we have

tan 60 = \frac{ad}{5\sqrt3} \\
\\
\sqrt 3=  \frac{ad}{5\sqrt3}\\
\\
ad= 5\sqrt3 \times \sqrt 3\\
\\
ad= 5\times 3\\
\\
ad=15

Thus, ad is 15 cm.


4 0
3 years ago
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