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2 years ago

The figure shows a parallelogram inside a rectangle outline:

Mathematics

2 answers:

Juli2301 [7.4K]2 years ago

6 0

A. 1/9 sq. ft.
take area of large rectangle (1/2 x 1/3) - 2 triangles area 2(1/2 x 1/3 x 1/6)
= 1/6 - 1/18 = 3/18 - 1/18 = 2/18 = 1/9

Tamiku [17]2 years ago

4 0

B.1/6

i think that's the answer

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Paul needs to buy 5_8pound of peanuts. The scale at the store measures parts of a pound in sixteenths. What measure is equivalen

ryzh [129]

Answer:

10 ÷ 16

Step-by-step explanation:

The computation is shown below

Given that

Paul required to buy 5 by 8 pound of peanuts

And, the scale at the store is in sixteenths

So, the measure that should be equivalent is

Here the denominator should be 16 so it should be multiplied by 2

= 5 ÷ 8 × 2 ÷ 2

= 10 ÷ 16

3 0

2 years ago

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

$lw+2lh+2wh = 64$

If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

7 0

3 years ago

PLEASE HELP GEOMETRY!!!

aliina [53]

The answer would be A

8 0

3 years ago

You need 3 sticks of butter for every 24 giant cookies you bake.

marta [7]

Answer:

Sticks of butter : 2

Number of cookies : 40

Step-by-step explanation:

Given that :You need 3 sticks of butter for every 24 giant cookies you bake.

----------------------------------------------------------------------------------------------------------

Sticks of butter Number of cookies

3 24

x 16

5 y

----------------------------------------------------------------------------------------------------------

Let the unknown be x and y..

Since you need 3 sticks of butter for every 24 giant cookies you back

Then 24/3 = 8

Since the number of cookies is 16 then 16/8 = 2

Thus x = 2

Next for y.

Since you need 3 sticks of butter for every 24 giant cookies you back

Then 5 * 8 = 40

Thus, y = 40

----------------------------------------------------------------------------------------------------------

Completed table below:

Sticks of butter Number of cookies

3 24

2 16

5 40

----------------------------------------------------------------------------------------------------------

~lenvy~

6 0

1 year ago

Read 2 more answers

Two horses are ready to return to their barn after a long workout session at the track. The horses are at coordinates H(1,10) an

lana [24]

Distance between points $\left(x_1,y_1\right)$ and $\left( x_2,y_2 \right)$ is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Distance from H to B:

$[tex]d=\sqrt{(10-(-3))^2+(1-(-9))^2}=\sqrt{169+100}=\sqrt{269}$ d=\sqrt{(1-(-3))^2+(10-(-9))^2}=\sqrt{16+361}=\sqrt{376}[/tex] units.

Distance from Z to B:

$d=\sqrt{(10-(-3))^2+(1-(-9))^2}=\sqrt{169+100}=\sqrt{269}$ units.

Horse Z is closer to the barn.

(The conversion to meters is not required; the question does not ask for actual distances, so "units" is OK.)

6 0

3 years ago