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3 years ago

Heeeeeeeeeeeeeeeeeeeeeellllllllllllllllllllllllllllllllllllllllllppppppppppppppppppppp

Mathematics

1 answer:

goldenfox [79]3 years ago

8 0

Answer:

its E.498

Step-by-step explanation: HOPE THIS HELPED....!

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A $125 item is discounted 28%. Find the amount of discount.

Ksenya-84 [330]

Answer:

$90

Step-by-step explanation:

125 x .28 is 35

125-35 is 90

6 0

2 years ago

Check all solutions to the equation. If there are no solutions, check "None."<br> x=-81

Elodia [21]

Answer:

none

Step-by-step explanation:

If a squared variable is equal to a negative number, all of the solutions are imaginary

There are no real solutions

8 0

3 years ago

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Solve 3(2z−4)=−6(2−z). help!!

marysya [2.9K]

Answer:

undefined

Step-by-step explanation:

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2 years ago

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Select and use the most direct method to solve 2x(x + 1.5) = -1. Describe and justify the methods you used to solve the quadrati

miskamm [114]

Step-by-step explanation:

Given that,

A quadratic equation,

2x(x + 1.5) = -1

We need to solve the quadratic equation. Firstly we need to simplify the above equation to form it as $ax^2+bx+c=0$ .

So,

$2x^2+3x=-1\\\\2x^2+3x+1=0$

Here, a = 2, b = 3 and c = 1

The roots of the given equation can be given by :

$x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Putting all the values we get :

$x=\dfrac{-b\pm \sqrt{b^2+4ac} }{2a}, \dfrac{-b\pm \sqrt{b^2-4ac} }{2a}\\\\x=\dfrac{-3\pm \sqrt{3^2+4(2)(1)} }{2(2)}, \dfrac{-3\pm \sqrt{3^2-4(2)(1)} }{2(2)}\\\\x=\dfrac{-3+1}{4}, \dfrac{-3-1}{4}\\\\x=-\dfrac{1}{2}, -1$

So, the roots of the given equation is -1/2 and -1.

5 0

3 years ago

Please help me!

Tomtit [17]

One question, are they congruent figures?

7 0

2 years ago