How does your Skeletal and Muscular Systems work together?

Na+ and Cl- __________ ___________________________ Na+ and PO4 3- __________ ___________________________ Na+ and SO4 2- ________

bagirrra123 [75]

Answer:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

The cations and anions being oppositely charged attract each other through strong coloumbic forces and form an ionic bond.

(1) Sodium is carrying +1 charge called as $Na^{+1}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $NaCl$ .

(2) Sodium is carrying +1 charge called as $Na^{+1}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $Na_3PO_4$ .

(3) Sodium is carrying +1 charge called as $Na^{+1}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $Na_2SO_4$ .

(4) Sodium is carrying +1 charge called as $Na^{+1}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $Na_2CO_3$ .

(5) Potassium is carrying +1 charge called as $K^{+1}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. They form $KCl$ .

(6) Potassium is carrying +1 charge called as $K^{+1}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. They form $K_3PO_4$ .

(7) Potassium is carrying +1 charge called as $K^{+1}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. They form $K_2SO_4$ .

(8) Potassium is carrying +1 charge called as $K^{+1}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. They form $K_2CO_3$ .

(9) Calcium is carrying +2 charge called as $Ca^{+2}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. They form $CaCl_2$ .

(10) Calcium is carrying +2 charge called as $Ca^{+2}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. They form $Ca_3(PO_4)_2$ .

(11) Calcium is carrying +2 charge called as $Ca^{+2}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. They form $CaSO_4$ .

(12) Calcium is carrying +2 charge called as $Ca^{+2}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. They form $CaCO_3$ .

(13) Ammonium ion is carrying +1 charge called as $NH_4^{+1}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. They form $NH_4Cl$ .

(14) Ammonium ion is carrying +1 charge called as $NH_4^{+1}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. They form $NH_4_3PO_4$ .

(15) Ammonium ion is carrying +1 charge called as $NH_4^{+1}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. They form $NH_4_2SO_4$ .

(16) Ammonium ion is carrying +1 charge called as $NH_4^{+1}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. They form $NH_4_2CO_3$ .

(17) Iron is carrying +3 charge called as $Fe^{+3}$ cation and chloride $Cl^{-1}$ is an anion carrying -1 charge. They form $FeCl_3$ .

(18) Iron is carrying +3 charge called as $Fe^{+3}$ cation and phosphate $PO_4^{-3}$ is an anion carrying -3 charge. They form $FePO_4$ .

(19) Iron is carrying +3 charge called as $Fe^{+3}$ cation and sulfate $SO_4^{-2}$ is an anion carrying -2 charge. They form $Fe_2(SO_4)_3$ .

(20) Iron is carrying +3 charge called as $Fe^{+3}$ cation and carbonate $CO_3^{-2}$ is an anion carrying -2 charge. They form $Fe_2(CO_3)_3$ .

7 0

3 years ago

What is the enthalpy in KJ of reaction for the initial combustion if the delta H for vaporization is 75.75 KJ and the net delta

Gnesinka [82]

Answer:

-775.75

Explanation:

4 0

2 years ago

There is a mixture of three gases. We know the total pressure is 2.50 atmosphere and the pressure of the oxygen and the nitrogen

Viktor [21]

Answer:

1.14 atm and 1.139 mol

Explanation:

The <em>total pressure</em> of the container is equal to the <u>sum of the partial pressure of the three gasses</u>:

P = Poxygen + Pnitrogen + Pcarbon dioxide

2.50 atm = 0.52 + 0.84 + Pcarbon dioxide

Now we <u>solve for the pressure of carbon dioxide</u>:

Pcarbon dioxide = 1.14 atm

To c<u>alculate the number of CO₂ moles </u>we use <em>PV=nRT</em>:

P = 1.14 atm

V = 25.0 L

n = ?

R = 0.082 atm·L·mol⁻¹·K⁻¹

T = 32 °C ⇒ 32 + 273.16 = 305.16 K

1.14 atm * 25.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 305.16 K

n = 1.139 mol

5 0

3 years ago

Given the following reaction and data, A + B → Products

natima [27]

Answer:

a. Rate = k×[A]

b. k = 0.213s⁻¹

Explanation:

a. When you are studying the kinetics of a reaction such as:

A + B → Products.

General rate law must be like:

Rate = k×[A]ᵃ[B]ᵇ

You must make experiments change initial concentrations of A and B trying to find k, a and b parameters.

If you see experiments 1 and 3, concentration of A is doubled and the Rate of the reaction is doubled to. That means a = 1

Rate = k×[A]¹[B]ᵇ

In experiment 1 and to the concentration of B change from 1.50M to 2.50M but rate maintains the same. That is only possible if b = 0. (The kinetics of the reaction is indepent to [B]

Rate = k×[A][B]⁰

b. Replacing with values of experiment 1 (You can do the same with experiment 3 obtaining the same) k is:

Rate = k×[A]

0.320M/s = k×[1.50M]

6 0

3 years ago

The volume of a gas at 17.5 psi decreases from 1.8L to 750mL. What is the new pressure of the gas in arm?

Maurinko [17]

Answer:

P₂ = 2.88 atm

Explanation:

Given data:

Initial volume of gas = 1.8 L

Final volume = 750 mL

Initial pressure = 17.5 Psi

Final pressure = ?

Solution:

We will convert the units first:

Initial pressure = 17.5 /14.696 = 1.2 atm

Final volume = 750 mL ×1L/1000L = 0.75 L

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume

Now we will put the values in formula,

P₁V₁ = P₂V₂

1.2 atm × 1.8 L = P₂ ×0.75 L

P₂ = 2.16 atm. L/ 0.75 L

P₂ = 2.88 atm

4 0

3 years ago