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Dominik [7]
3 years ago
6

What volume will 12.0 g of oxygen gas occupy at 25 c and a pressure of 52.7 kpa?

Chemistry
1 answer:
Stolb23 [73]3 years ago
8 0
We can use the ideal gas law equation to find the volume occupied by oxygen gas
PV = nRT
where ;
P - pressure - 52.7 kPa
V - volume 
n - number of oxygen moles - 12.0 g / 32 g/mol = 0.375 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 25 °C + 273 = 298 K
substituting the values in the equation 
52 700 Pa x V = 0.375 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
 V = 17.6 L
volume of the gas is 17.6 L
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The formula is:

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At beginning, V1 = 100%, n1 = 100%,

As the chemist removes 21% of the gas, 79% of moles remain = n2.

Replacing:

100% / 100% = V2 / 79%

V2 = 79%, that means:

<h3>The volume of the gas decreases also in a 21% based on the Avogadro's law</h3>
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