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3 years ago

What volume will 12.0 g of oxygen gas occupy at 25 c and a pressure of 52.7 kpa?

1 answer:

8 0

We can use the ideal gas law equation to find the volume occupied by oxygen gas
PV = nRT
where ;
P - pressure - 52.7 kPa
V - volume
n - number of oxygen moles - 12.0 g / 32 g/mol = 0.375 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 25 °C + 273 = 298 K
substituting the values in the equation
52 700 Pa x V = 0.375 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
V = 17.6 L
volume of the gas is 17.6 L

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58. A cylinder of a gas mixture used for calibration of blood gas analyzers in medical laboratories contains 5.0% CO2, 12.0% O2,

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Answer and Explanation:

$Greetings!$

$Let's~answer~your~question!$

$Partial ~pressure ~of ~gas ~can ~be ~directly~ calculated ~by ~multiplying ~the~ percentage\\ of~ pressure~ of~ gases~ to ~the ~total ~pressure.$

$\boxed{Pgas~ = ~P~total~ * \% ~P ~of ~gas}$

For % of N2 gas: 

 $100\% - (5\% + 12\%) = 83\% ~N2$ 

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