Answer:
The equation shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A, in astronomical units, AU. If planet Y is twice the mean distance from the sun as planet X, by what factor is the orbital period increased?
Step-by-step explanation:
Hello!
We know that from midnight to 6am the temperature went up 8° and at 6am it was -21°
To find what it was at midnight we have to work backwards
Since it went up we have to subtract 8 from -21
-21 - 8 = -29
The answer is -29°C
Hope this helps!
1000, because if it’s number 0-9 you have 10 options for the first possible number, then multiply by 10 two more time for the second and third number .but if it’s wrong I’m srry rip ;P
So say for example u have -7 - (-5), think of subtracting integers as adding the opposite, so ur adding the opposite of -5, the opposite of -5 is 5, so ur adding -7 and 5= -2
another one: -15 - (-18)
again, adding the opposite. -15 plus positive 18= 3
Answer:
(C)x=11.6, y=23.2
Step-by-step explanation:
Using Theorem of Intersecting Secant and Tangent
Applying this theorem in the diagram, we have:
Next, we apply Theorem of Intersecting Chords
PV X VQ=SV X VR
4 X x= 2 X y
Recall earlier we got: x=11.6
2y=4 X 11.6
2y=46.4
Divide both sides by 2
y=46.4/2=23.2
Therefore: x=11.6, y=23.2
