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Answer:
First compute the characteristic length and the Biot number to see if the lumped analysis is applicable
Lc = V/A = (pie*D3/6) / (pie * D2)= 1.2/6 = 0.0012/6= 0.0002m
Bi = hLc/K = (110W/m2.oC)(0.0002)(moC/35W)= 110*0.0002/35 = 0.0006 less than 0.1
Since the Biot number is less than 0.1, we can use the lumped parameter analysis.
In such an analysis, the time to reach a certain temperature is given by
t = -1/bIn(T-Tinfinite/T - Tinfinite)
From the data in the problem we can compute the parameter, b, and then compute the time for the ratio (T – Tinfinite/(Ti – Tinfinite) to reach the desired value.
b = hA/pCpV = h/pCpLc = 110/8500*0.0002 *320*s
b = 110/544s = 0.2022/s
The problem statement is interpreted to read that the measured temperature difference T – Tinfinite has eliminated 98.5% of the transient error in the initial temperature reading Ti – Tinfinite so the value of value of (T – Tinfinite)/(Ti – Tinfinite) to be used in this equation is 0.015
t = -1/bIn(T-Tinfinite/T - Tinfinite)
t = -s/0.1654 (In0.015)
t = (-s*-4.1997)/0.2022
t = 20.77s
It will take the thermocouple 20.77s to reach 98.5% of the initial temperature
Answer:
The answer is below
Explanation:
Let A represent the first switch, B represent the second switch and C represent the bulb. Also, let 0 mean turned off and 1 mean turned on. Since when both switches are in the same position, the light is off. This can be represented by the following truth table:
A B C (output)
0 0 0
0 1 1
1 0 1
1 1 0
The logic circuit can be represented by:
C = A'B + AB'
The output (bulb) is on if the switches are at different positions; if the switches are at the same position, the output (bulb) is off. This is an XOR gate. The gate is represented in the diagram attached below.
Answer:
They are specializing in areas such as crop rotation, irrigation & drainage, planet breeding, soil science, weed control & disease & pest control.
Explanation:
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