The maximum height that the water can rise above the jet is: 35 meters.
<h3>Maximum height that the water can rise above the jet</h3>
Given:
P = 350 kPa = 350000 Pa
We would use pressure(p) formula to determine the maximum height that the water can rises above the jet by solving for h (height).
Using this formula
Pressure(P) = P₀ + ρgh
Where;
P₀ represent Pressure at the fluid's surface
ρ represent Density of the fluid = 1000 kg/m³
g represent acceleration due to gravity = 10 m/s².
h represent height
Solving for h (height)
350000 = 0 + (1000 × 10 ×h)
350000 = 10000h
Divide both side by 10000h
h = 350000/10000
h = 35 meters
Therefore the maximum height that the water can rise above the jet is: 35 meters.
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Answer:
Basics. CNG is a readily available alternative to gasoline that's made by compressing natural gas to less than 1% of its volume at standard atmospheric pressure. ... Expanding the numbers of CNG fueling stations would allow for the increase of CNG vehicles on U.S. roads.
Answer:
Explanation:
Force on Q₃ due to charge Q₁
= 9 x 10⁹x 4 x 10⁻⁹ x1 x 10⁻⁹ / 5²
= 1.44 x 10⁻⁹ N
Force due to Q₂ will also be 1.44 x 10⁻⁹ N
component of these forces along x axis
-= 2 x 1.44 x 10⁻⁹ cosθ
= 2.88 x 10⁻⁹ x 4/5
= 2.30x10⁻⁹ N along x axis.
The y-component will calcel out.
b ) In this case , Q₁ will repel and Q₂ will attract.
In this case Q₁ will repel and Q₂ will attract. Component along y - axis will be same as earlier one or 2.30x10⁻⁹ N . Component along x axis will cancel out.
c ) Electric field in case 1 and case 2 will be
= 2.30x10⁻⁹ / 1 x 10⁻⁹
= 2.3 N / C , because field is force per unit charge. The sane field will be in case 2 .
Answer:
the value of conductivity in IP is 
Explanation:
Given that
Thermal conductivity K=14.54 W/m.K
This above given conductivity is in SI unit.
SI unit IP unit Conversion factor
m ft 0.3048
W Btu/hr 0.293
The unit of conductivity in IP is Btu./ft.hr.F.
Now convert into IP divided by 1.73 factor.
So
So the value of conductivity in IP is
Answer:
Explanation:
This is a questions that can be answered using electrical resistance analogy. The expression for the
