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skad [1K]
3 years ago
7

The _______ is a tendency to assume that people with one positive attribute (e.g., who are physically attractive) also have othe

r positive traits.
Engineering
1 answer:
morpeh [17]3 years ago
7 0

Answer:

Halo effect

Explanation:

In psychology, halo effect is defined as the tendency to assume that people with one positive attribute (e.g. physical attractiveness) also have other positive traits. Mere Exposure is the tendency to feel more positively toward a stimulus as a result of repeated exposure to it.

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Argon is compressed in a polytropic process with n = 1.2 from 100 kPa and 30°C to 1200 kPa in a piston–cylinder device. Determin
gulaghasi [49]

Answer:

<em>181 °C</em>

<em></em>

Explanation:

Initial pressure P_{1} = 100 kPa

Initial temperature T_{1} = 30 °C = 30 + 273 K = 303 K

Final pressure P_{2} = 1200 kPa

Final temperature T_{2} = ?

n = 1.2

For a polytropic process, we use the relationship

(T_{2}/T_{1} ) = (P_{2}/P_{1})^γ

where γ = (n-1)/n

γ = (1.2-1)/1.2 = 0.1667

substituting into the equation, we have

(T_{2}/303) = (1200/100)^0.1667

T_{2}/303 = 12^0.1667

T_{2}/303 = 1.513

T_{2} = 300 x 1.513 = 453.9 K

==> 453.9 - 273 = 180.9 ≅ <em>181 °C</em>

5 0
3 years ago
What could happen in the aviation
Alina [70]

Answer:

Yes

Explanation:

7 0
3 years ago
what do you expect the future trends of an operating system in terms of (a) cost (b) size (c) multitasking (d) portability (e) s
tino4ka555 [31]

Answer:

plz follow in titkok

Explanation:

3 0
3 years ago
Select four items that an industrial engineer must obtain in order to practice in the field.
alex41 [277]

Answer:

Professional engineering license

Bachelor's degree

Computer science classes

job recommendations

3 0
2 years ago
Read 2 more answers
An engineer measures a sample of 1200 shafts out of a certain shipment. He finds the shafts have an average diameter of 2.45 inc
Vadim26 [7]

Answer: 78.89%

Explanation:

Given : Sample size : n=  1200

Sample mean : \overline{x}=2.45

Standard deviation : \sigma=0.07

We assume that it follows Gaussian distribution (Normal distribution).

Let x be a random variable that represents the shaft diameter.

Using formula, z=\dfrac{x-\mu}{\sigma}, the z-value corresponds to 2.39 will be :-

z=\dfrac{2.39-2.45}{0.07}\approx-0.86

z-value corresponds to 2.60 will be :-

z=\dfrac{2.60-2.45}{0.07}\approx2.14

Using the standard normal table for z, we have

P-value = P(-0.86

=P(z

Hence, the percentage of the diameter of the total shipment of shafts will fall between 2.39 inch and 2.60 inch = 78.89%

7 0
3 years ago
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