Answer:
<em>181 °C</em>
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Explanation:
Initial pressure
= 100 kPa
Initial temperature
= 30 °C = 30 + 273 K = 303 K
Final pressure
= 1200 kPa
Final temperature
= ?
n = 1.2
For a polytropic process, we use the relationship
(
/
) = (
/
)^γ
where γ = (n-1)/n
γ = (1.2-1)/1.2 = 0.1667
substituting into the equation, we have
(
/303) = (1200/100)^0.1667
/303 = 12^0.1667
/303 = 1.513
= 300 x 1.513 = 453.9 K
==> 453.9 - 273 = 180.9 ≅ <em>181 °C</em>
Answer:
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Answer: 78.89%
Explanation:
Given : Sample size : n= 1200
Sample mean : 
Standard deviation : 
We assume that it follows Gaussian distribution (Normal distribution).
Let x be a random variable that represents the shaft diameter.
Using formula,
, the z-value corresponds to 2.39 will be :-

z-value corresponds to 2.60 will be :-

Using the standard normal table for z, we have
P-value = 

Hence, the percentage of the diameter of the total shipment of shafts will fall between 2.39 inch and 2.60 inch = 78.89%