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Savatey [412]
3 years ago
10

What is the IUPAC name for this compound?

Chemistry
1 answer:
Dovator [93]3 years ago
5 0

Answer:

2–methyl–2–propanol.

Explanation:

To name the compound given in the question above, we must:

1. Identify the functional group and it's location on the compound.

2. Locate the longest continuous carbon chain. This gives the parent name of the compound.

3. Identify the substituent group attached to the compound.

4. Locate the position of the substituent group.

5. Combine the above to obtain the name of the compound.

Thus, we can obtain the name of the compound as follow:

1. The functional group of the compound is alkanol (alcohol). It is located at carbon 2.

2. The longest continuous carbon chain is 3. Since the compound is an alcohol, parent name of the compound will change from propane to propanol.

3. The substituent group attached to the compound is methyl i.e –CH3.

4. The methyl group is located at carbon 2.

5. The name of the compound is

2–methyl–2–propanol.

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5 0
3 years ago
Suppose 0.795 g of sodium iodide is dissolved in 100. mL of a 39.0 m M aqueous solution of silver nitrate.
lubasha [3.4K]

Answer:

The final molarity of iodide anion is 0.053 M

Explanation:

<u>Step 1</u>: Data given

Mass of sodium iodide (NaI) = 0.795 grams

Volume of the solution = 100 mL = 0.1 L

Molarity of aqueous solution of silver nitrate (AgNO3) = 39 mM = 0.039M

The molecular mass of sodium iodide is 149.89 g/mol.

<u>Step 2:</u> The balanced equation

AgNO3(aq) + NaI(aq) → AgI(s) + NaNO3(aq)

<u>Step 3: </u>Calculate number of moles of sodium iodide

Moles NaI = mass NaI / Molar mass NaI

Moles NaI = 0.795 grams / 149.89 g/mol

Moles NaI = 0.0053 moles

For 1 mole AgNO3 consumed, we need 1 mole NaI to produce 1 mole AgI and 1 mole NaNO3

The sodium iodide will dissociate as followed:

NaI(aq) → Na+(aq) +  I-(aq)

<u>Step 4</u>: Calculate iodide ions

For 1 mole NaI, we have 1 mole of I-

For 0.0053 moles of NaI we'll have 0.0053 moles I-

<u>Step 5:</u> Calculate molarity of iodide ion

Molarity = moles I- / volume

Molarity I- = 0.0053 moles / 0.1 L

Molarity I- = 0.053 M

The final molarity of iodide anion is 0.053 M

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3 years ago
In which aqueous solution will the most ZnS dissolve?
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That what I found 0.1 M NaCl
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3 years ago
URGENT!!!! helppp<br><br> convert 22.63 moles of oxygen to volume
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I
0.5
I hope this helps
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