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3 years ago

What is the IUPAC name for this compound?

Chemistry

1 answer:

Dovator [93]3 years ago

5 0

Answer:

2–methyl–2–propanol.

Explanation:

To name the compound given in the question above, we must:

1. Identify the functional group and it's location on the compound.

2. Locate the longest continuous carbon chain. This gives the parent name of the compound.

3. Identify the substituent group attached to the compound.

4. Locate the position of the substituent group.

5. Combine the above to obtain the name of the compound.

Thus, we can obtain the name of the compound as follow:

1. The functional group of the compound is alkanol (alcohol). It is located at carbon 2.

2. The longest continuous carbon chain is 3. Since the compound is an alcohol, parent name of the compound will change from propane to propanol.

3. The substituent group attached to the compound is methyl i.e –CH3.

4. The methyl group is located at carbon 2.

5. The name of the compound is

2–methyl–2–propanol.

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Help please fast will mark as Brainliest

wlad13 [49]

Answer:

The answer is 2i on right hand side.

Explanation:

We should star by checking the equation from right.

First we check how many Zn r there in left hand side. Which is 1. Let us check how many Znr there in right hand side, there is 1.So Zn is balanced, and don't worry about Znplus2 on right hand side it is just the ions not how many zinc r there.

Now let us check how many I are there left hand side. Which is 2. Now how many I are there in right hand side? Only 1.

So we put 2 behind I.

Now there r 2 I on both sides.

Its simple actually.

3 0

3 years ago

Read 2 more answers

What is the vapor pressure of CS2CS2 in mmHgmmHg at 26.5 ∘C∘C? Carbon disulfide, CS2CS2, has PvapPvap = 100 mmHgmmHg at −−5.1 ∘C

Digiron [165]

Answer: 26.5 mm Hg

Explanation:

The vapor pressure is determined by Clausius Clapeyron equation:

$ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}(\frac{1}{T_1}-\frac{1}{T_2})$

where,

$P_1$ = initial pressure at $26.5^oC$ = ?

$P_2$ = final pressure at $-5.1^oC$ = 100 mm Hg

= enthalpy of vaporisation = 28.0 kJ/mol =28000 J/mol

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = $26.5^oC=273+26.5=299.5K$

$T_2$ = final temperature = $-5.1^oC=273+(-5.1)=267.9K$

Now put all the given values in this formula, we get

$\log (\frac{P_1}{100})=\frac{28000}{2.303\times 8.314J/mole.K}[\frac{1}{299.5}-\frac{1}{267.9}]$

$\log (\frac{P_1}{100})=-0.576$

$\frac{P_1}{100}=0.265$

$P_1=26.5mmHg$

Thus the vapor pressure of $CS_2CS_2$ in mmHg at 26.5 ∘C is 26.5

7 0

3 years ago

Vitamin C has an empirical formula of C3H4O3 and a molecular mass of 176 amu. What is the molecular formula of vitamin C?

Vinvika [58]

Answer:

(C3H4O3) x 2 = C6H8O6, the molecular formula for Vitamin C.

3 0

3 years ago

Someone please help will mark as brainliest

d1i1m1o1n [39]

Answer:

solution:-a homogenous mixture of two or more substances in relative amounts that can be varied continuously up to what is called the limit of solubility.

solute:-is a substance, usually a solid, that is dissolved in a solution, which is usually a liquid.

solvent:-substance, ordinarily a liquid, in which other materials dissolve to form a solution.

polar molecule:-is a molecule in which one end of the molecule is slightly positive, while the other end is slightly negative.

Nonpolar molecules occur when electrons are shared equal between atoms of a diatomic molecule or when polar bonds in a larger molecule cancel each other out.

concentration refers to the amount of a substance in a defined space.

Explanation:

6 0

3 years ago

What is the energy of a photon with a frequency of 9.50 x 1013 Hz?

Taya2010 [7]

Answer:

$\huge{6.295 \times {10}^{ - 20} \: J}$

Explanation:

The energy of the photon can be found by using the formula

E = hf

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question we have

E = 6.626 × 10-³⁴ × 9.5 × 10¹³

We have the final answer as

$6.295 \times {10}^{ - 20} \: J$

Hope this helps you

3 0

2 years ago