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Alexeev081 [22]
3 years ago
7

Fill in the reaction type and predicted products for:

Chemistry
1 answer:
Andrej [43]3 years ago
8 0
IUPAC = no answer sorry but subscribe are not
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The following balanced equation shows the formation of ethane (C2H6).
almond37 [142]

Answer:

C

Explanation:

Well, we can see from the equation that hydrogen gas and ethane are in a 2:1 ratio based on their mole coefficients.

You need 2 mol H2 to make 1 mol C2H6. So that means you need 2*13.78 mol H2 to make 13.78 mol C2H6!

2*13.78 = 27.56 mol

C is correct.

4 0
4 years ago
In an accident, a solution containing 2.5 kg of nitric acid was spilled. Two kilograms of Na2CO3 was quickly spread on the area
storchak [24]

First we must write a balanced chemical equation for this reaction

Na_2CO_3 _(_a_q_)+ 2HNO_3_(_a_q_) \implies 2NaNO_3_(_s_) + CO_2_(_g_) + H_2O_(_l_)

The mole ratio for the reaction between HNO_3 and Na_2CO_3 is 1:2. This means 1 moles of Na_2CO_3 will neutralize 2 moles HNO_3. Now we find the moles of each reactant based on the mass and molar mass.

2500g HNO_3 \times \frac{mol}{63.01g\ HNO_3} = 39.67 mol\ HNO_3

2000g\ Na_2CO_3 \times \frac{mol}{105.99g \ Na_2CO_3} = 18.87 mol\ Na_2CO_3

\frac{18.87 mol Na_2CO_3}{39.67\ HNO_3} = \frac{1 molNa_2CO_3}{2 mol HNO_3}

The Na_2CO_3 was enough to neutralize the acid because 18.87:39.67 is the same as 1:2 mol ratio.

4 0
4 years ago
Which area is most likely closest to a salt marsh or an estuary?
Archy [21]

Answer:

coastal area with very high tides deep ocean water miles from a river's mouth

Explanation:

Marshes are a type of wetland ecosystem where water covers the ground for long periods of time. Marshes are dominated by herbaceous plants, such as grasses, reeds, and sedges(National Geographic Society).

hope dis help

4 0
3 years ago
Given: There are 39.95 grams of Argon (39.95 g/1 mole) and one mole has a volume of 22.4 Liters (1 mole/22.4 L). What is the vol
marta [7]

Answer:

V_2=19.23L

Explanation:

Hello,

In this case, by using the Avogadro's law which allows us to understand the volume-moles behavior as a directly proportional relationship:

\frac{V_2}{n_2} =\frac{V_1}{n_1}

We can compute the volume of 34.3 g of argon by representing it in mole as shown below:

n_1=1 mol\\\\n_2=34.3g*\frac{1mol}{39.95g} =0.859mol

Thus, we find:

V_2=\frac{V_1*n_2}{n_1}=\frac{22.4L*0.859mol}{1mol} \\\\V_2=19.23L

Best regards.

6 0
3 years ago
Elements in the same group (family) appeared to have the same what? 
Radda [10]
I think it's D- Number of neutrons
3 0
4 years ago
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