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HACTEHA [7]
2 years ago
12

What type of soils are more likely to transmit contaminants

Chemistry
2 answers:
Firlakuza [10]2 years ago
7 0

Answer:

HHAHAHDSHBDBFHFBJDKFHDFJGKFGJDFGHFHIUGHFDDFNDLS

Explanation:

Sindrei [870]2 years ago
4 0

Answer:

Chemicals can attach more easily to soils with a higher content of clay and organic matter. In addition, sandy soils generally do not contain a large amount of soil organisms compared with other soil types.

Explanation:

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Water glass is found in
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Answer:

liquid form

Explanation:

am i right? if right like

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3 years ago
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Which elements are present in the compound aluminium nitrate?
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Answer:

Aluminum nitrate is a salt composed of aluminum and nitric acid, belonging to a group of reactive chemicals - organic nitrate and nitrite compounds. The nitrate ion is polyatomic, meaning it is composed of two or more ions that are covalently bonded. This ion makes up the conjugate base of nitric acid.

Explanation:

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Which of these solution is most basic
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What are two variables that affect kinetic energy
zubka84 [21]

The answer for the following questions is explained below.

Explanation:

The two variables that affect kinetic energy are:

  1. mass    and
  2. velocity

  • velocity - The faster an object moves,the more the kinetic energy it has.
  • mass - Kinetic energy increases as mass increases

The kinetic energy of an object depends on both its mass and its velocity

Kinetic energy increases as mass increases

For example,think about rolling a bowling ball and a golf ball down a bowling lane at same velocity

Here,the bowling ball has more mass than the golf ball

Therefore you use more energy to roll the bowling ball than to roll the golf ball

The bowling ball is more likely to knock down the pins because it has more kinetic energy than the golf ball

7 0
3 years ago
The rate of effusion of an unknown gas was measured and found to be 11.9 mL/min. Under identical conditions, the rate of effusio
iren2701 [21]

Answer : The correct option is, (B) CO_2

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

R\propto \sqrt{\frac{1}{M}}

or,

(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}       ..........(1)

where,

R_1 = rate of effusion of unknown gas = 11.9\text{ mL }min^{-1}

R_2 = rate of effusion of oxygen gas = 14.0\text{ mL }min^{-1}

M_1 = molar mass of unknown gas  = ?

M_2 = molar mass of oxygen gas = 32 g/mole

Now put all the given values in the above formula 1, we get:

(\frac{11.9\text{ mL }min^{-1}}{14.0\text{ mL }min^{-1}})=\sqrt{\frac{32g/mole}{M_1}}

M_1=44.2g/mole

The unknown gas could be carbon dioxide (CO_2) that has approximately 44 g/mole of molar mass.

Thus, the unknown gas could be carbon dioxide (CO_2)

5 0
3 years ago
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